将给定的节点链（链表）一分为二，返回另一半
[英]Splits the given node chain (linked list) in half, returning the second half
问题描述
I would like to Splits the given node chain(linked list) in half, returning the second half.
我想将给定的节点链（链表）一分为二，返回另一半。 If the given chain has an odd length, the extra node is part of the second half of the chain.如果给定链的长度为奇数，则额外节点是链后半部分的一部分。
1 个解决方案
解决方案1
0 2019-02-15 04:03:54
I wont do your homeworks but here are some things that can help you:我不会做你的功课，但这里有一些可以帮助你的事情：
- What is the length of the chain (to know where to stop)链条的长度是多少（知道在哪里停止）
- How can I find the length of the chain我怎样才能找到链条的长度
- How can I use that information to stop on the correct node我如何使用该信息在正确的节点上停止
- Once I am there, what do I return, what am I doing ?一旦我到了那里，我要返回什么，我在做什么？
- Is it correct ?这是正确的吗 ？ I should test it to be sure.我应该测试它以确保。
- Success !!!成功 ！！！
声明:本站的技术帖子网页，遵循CC BY-SA 4.0协议，如果您需要转载，请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.
相关问题
我们如何对链表重新排序 - 反转后半部分并将每个相邻元素一一连接到前半部分？ - How do we reorder a linked list- reversing the second half and connecting every adjacent element to the first half one by one?
我怎样才能给这个列表的前半部分一个 A，给后半部分一个 B？ - How can I give an A to first half of this list and a B to the second half?
打印链表的第二半 - Print 2nd half of the Linked List
在某些情况下排序列表的后半部分不起作用 - Sorting Second Half of a List Not Working in Some Cases
如何从字典中获取列表的后半部分 - How to get the second half of a list from a dictionary
大写字符串的后半部分 - Uppercase second half of a string
如何将列表列表的后半部分作为列表列表？ - How to get the second half of a list of lists as a list of lists?
为什么在合并排序的递归调用中对列表的后半部分进行注释操作 - Why the second half of list is note operated on in a recursive call in merge sort
正则表达式重新查找上半部分，但保留下半部分 - re regex find first half but keep second half of line
如何在python中按升序排序前半部分，按降序排序后半部分？ - How to sort first half in ascending and second half in descending order in python?
相关标签