[英]Print file in particular order in awk
I am following this link https://stackoverflow.com/a/54599800/10220825 我正在关注此链接https://stackoverflow.com/a/54599800/10220825
file.txt file.txt的
Iteration 1
RAM: +2s
Cache: +142ms (total +417ms)
Iteration 2
RAM: +184ms
Cache: +172ms
Searchms: +131ms (total +385ms)
Iteration 3
RAM: +149ms
Searchms: +3.2s
I want to remove the ms or s
from the time value but not from name (example it should not remove Searchms to Search). 我想从时间值中删除ms or s
,但不从名称中删除(例如,它不应删除Searchms到Search)。 Also I want to convert s into ms
by multiply into 1000
if the time value contains s
and print result accordingly. 另外,如果时间值包含s
,我想通过multiply into 1000
将s into ms
转换s into ms
并相应地打印结果。
Expected Output: 预期产量:
RAM: 2000 184 149
Cache: 142 172
Searchms: 131 3200
try.awk try.awk
/:/{vals[$1]=vals[$1] OFS $2+0}
END {
for (key in vals)
print key vals[key]
}
On executing : awk -f try.awk file.txt
执行时: awk -f try.awk file.txt
Code Output: 代码输出:
Cache: 142 172
Searchms: 131 3.2
RAM: 2 184 149
In my output s is not converting to ms.
在我的输出中, s is not converting to ms.
Please suggest me how I modify above source code try.awk
to convert s to ms. 请建议我如何修改上述源代码try.awk
将s转换为ms。
New Test Case: file.txt 新的测试用例: file.txt
Iteration 1
RAM: +2s342ms
Iteration 2
RAM: +2s
Iteration 3
RAM: +149ms
Code: 码:
/:/ && $2 ~/ms$/{vals[$1]=vals[$1] OFS $2+0;next}
/:/ && $2 ~/[^m]s$/{vals[$1]=vals[$1] OFS ($2+0)*1000}
END {
for (key in vals)
print key vals[key]
}
Expected output: 预期产量:
RAM: 2342 2000 149
Output: 输出:
RAM: 2 2000 149
You can use the following awk
script: 您可以使用以下awk
脚本:
/:/ && $2 ~/ms$/{vals[$1]=vals[$1] OFS $2+0;next}
/:/ && $2 ~/[^m]s$/{vals[$1]=vals[$1] OFS ($2+0)*1000}
END {
for (key in vals)
print key vals[key]
}
This will produce the output: 这将产生输出:
awk -f try.awk file.txt
Cache: 142 172
Searchms: 131 3200
RAM: 2000 184 149
Explanations: 说明:
$2 ~/ms$/
will check if we have a line with ms
in this case the same logic is done as before and the next
will force awk
to jump to the next line. 条件$2 ~/ms$/
将检查如果我们有一个线ms
在这种情况下,相同的逻辑作为之前完成和next
将迫使awk
跳转到下一行。 /:/ && $2 ~/[^m]s$/{vals[$1]=vals[$1] OFS ($2+0)*1000}
when we reach this scope we know that we have a line with units in s
and we multiply it by 1000 to convert it to ms
. /:/ && $2 ~/[^m]s$/{vals[$1]=vals[$1] OFS ($2+0)*1000}
当我们到达此范围时,我们知道我们有一条线,单位为s
和我们将其乘以1000即可将其转换为ms
。 To answer to your new requirements, I have adapted the try.awk
into: 为了满足您的新要求,我将try.awk
为:
/:/ && $2 ~/[0-9]+s[0-9]+ms$/{split($2,buff,/s/);vals[$1]=vals[$1] OFS (buff[1]+0)*1000+buff[2];next}
/:/ && $2 ~/ms$/{vals[$1]=vals[$1] OFS $2+0;next}
/:/ && $2 ~/[^m]s$/{vals[$1]=vals[$1] OFS ($2+0)*1000}
END {
for (key in vals)
print key vals[key]
}
Input: 输入:
$ cat file2.txt
Iteration 1
RAM: +2s342ms
Iteration 2
RAM: +2s
Iteration 3
RAM: +149ms
Output: 输出:
$ awk -f try.awk file2.txt
RAM: 2342 2000 149
A small adaptation of the OP: OP的小改编:
/:/{ vals[$1]=vals[$1] OFS $2*($2~/ms$/ ? 1 : 1000 ) }
END { for (key in vals) print key vals[key] }
Remark: this will not work on all versions of awk, this makes use of the following nifty feature of gawk (and POSIX): 备注:这不适用于所有版本的awk,这利用了gawk(和POSIX)的以下出色功能:
A string is converted to a number by interpreting any numeric prefix of the string as numerals: "2.5" converts to 2.5, "1e3" converts to 1,000, and "25fix" has a numeric value of 25 . 通过将字符串的任何数字前缀解释为数字,可以将字符串转换为数字:“ 2.5”转换为2.5,“ 1e3”转换为1,000, “ 25fix”的数字值为25 。 Strings that can't be interpreted as valid numbers convert to zero. 无法解释为有效数字的字符串将转换为零。
source: Gnu Awk manual: Conversion of Strings and Numbers 来源: Gnu Awk手册:字符串和数字的转换
This behaviour is Posix valid and works using the C-function atof
. 此行为是Posix有效的,并使用C函数atof
起作用。 POSIX, however, gives a second option to convert strings to numbers where "25fix" would convert to 0. This is, for example, the case on Oracle: 但是,POSIX提供了将字符串转换为数字的第二个选项,其中“ 25fix”将转换为0。例如,在Oracle上就是这种情况:
Linux: GNU $ awk 'BEGIN{print "25fix"+0}'
25
SUN OS: SUNWesu $ /usr/bin/awk 'BEGIN{print "25fix"+0}'
0
SUN OS: SUNWxpg $ /usr/xpg4/bin/awk 'BEGIN{print "25fix"+0}'
25
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