成功登录后将CAS重定向到URL

Question

Here a solution is described to handle redirects to a custom URL based on a condition via use of AccessStrategy .

This however is part of the unauthorized login logical flow therefore results into a still not-logged in user arriving at the end url we redirect to. (via getUnauthorizedUrl )

If we want to redirect the user based on a condition, say via injecting an action to the webflow, how can we manipulate the return URL to be changed into a custom one?

WebUtils.getService(requestContext) include getters of the source/originalUrl but no obvious way to set/manipulate said value through an action bean.

ps Currently using CAS version 5.3.x

Answer 1

Responses for normal web applications from CAS are built using WebApplicationServiceResponseBuilder .

If you examine this block you will find that the final response is built using WebApplicationServiceResponseBuilder bean. It is only created conditionally, if an existing bean is not already found in the context by the same name. So to provide your own, you just need to register a bean with the same name using your own @Configuration class.

@Bean
public ResponseBuilder<WebApplicationService> webApplicationServiceResponseBuilder() {
    return new MyOwnWebApplicationServiceResponseBuilder(...);
}

...and then proceed to design your own MyOwnWebApplicationServiceResponseBuilder , perhaps even by extending WebApplicationServiceResponseBuilder and overriding what you need where necessary to build the final redirect logic conditionally.

To learn about how @Configuration classes work in general, you can:

• Review this post
• or this post
• or consult the documentation for Spring and/or Spring Boot.