成员引用基类型 &#39;std::vector<char> *[10]&#39; 不是结构体或联合体

Question

I have the following problem: I´m trying to to some simple push in my class but its no working..

 #include <stdio.h>
 #include <iostream>
 #include <vector>

 template <size_t B, size_t N, typename T = char>
 class Number
 {
   private:
     std::vector<T>* v[N];
     int toBase(int valor);

   public:
     Number(int valor);
     Number <B,N,T> suma(const Number<B,N,T>& sumando) const;
    //ostream& write(ostream& os)const;
 };

 template <size_t B, size_t N, typename T>
 Number<B,N,T>::Number(int valor)
 {
   toBase(valor);
 }


 template <size_t B, size_t N, typename T>
 int Number<B,N,T>::toBase(int valor)
 {
    for(int i = 0; i < N; i++) {
     int aux = valor % B;
     v.push_back(aux); // PROBLEM HERE
   }
 }

  template <size_t B, size_t N, typename T>
  Number<B,N,T> Number<B,N,T>::suma(const Number<B,N,T>& sumando) const
  {
    //sumando.toBase();
  }

The compiler says "member reference base type 'std::vector *[10]' is not a structure or union v.push_back(aux);"

I think the problem starts with my vector *v. Maybe i cant use push_back because its a pointer? I dont know..

Any ideas? Thank you.

Answer 1

You're making this way more complicated than it needs to be and just confusing yourself. Change your class to this

 class Number
 {
   private:
     std::vector<char> v;
     int toBase(int valor);

   public:
     Number(int valor);
     Number suma(const Number& sumando) const;
    //ostream& write(ostream& os)const;
 };

You're trying to split a number into it's digits and put them in a vector. So just write a simple class with a vector like above. No templates or pointers or arrays are required for what you are trying to do.