二进制表达式（&#39;std :: ostream&#39;（aka&#39;basic_ostream <char> &#39;）和&#39;const std :: vector <int> “）

Question

I have the following problem. I´m just trying to output a vector but it says "invalid operands to binary expression ('std::ostream' (aka 'basic_ostream') and 'const std::vector')"

Code:

#include <stdio.h>
#include <iostream>
#include <vector>




template <size_t B, size_t N, typename T = int>
class Number
{

  private:
   std::vector<T> v[N]; // Vector que contendrá el numero desglozado
   void toBase(int valor);

 public:
   Number(int valor); // Constructor
   Number <B,N,T> suma(const Number<B,N,T>& sumando) const;
   std::ostream& write(std::ostream& os)const;
 };


template <size_t B, size_t N, typename T>
Number<B,N,T>::Number(int valor)
{
  toBase(valor);
  std::cout << write() << std::endl;
}



template <size_t B, size_t N, typename T>
void Number<B,N,T>::toBase(int valor)
{
   for(int i = 0; i < N; i++) {
    int aux = valor % B;
    v[i].push_back(aux);
  }
}



template <size_t B, size_t N, typename T>
std::ostream& Number<B,N,T>::write(std::ostream& os) const
{
  for(int i = 0; i < N; i++){
    os << v[i] << std::endl;
   }
}

I thought the problem was that i was trying to output the vector with a simple for loop. So i tried to output it with an ostream but i have the same error. So the ostream its ok i think. Just the outputting vector is the problem and i dont know why. Any ideas? Thanks you!

main:

#include <stdio.h>
#include <iostream>

#include "number.hpp"


int main() {

Number<2,10> N1(100);
Number<2,10> N2(200);

}

Answer 1

It seems you confused with braces.

std::vector<T> v[N];

You declaration above declares the array of vectors. I think you want to declare a vector with 4 elements/digits. In this case you have to use other braces:

std::vector<T> v{N};