检查字符串中的字符是否与列表的索引范围匹配？

Question

I am trying to create a password generator. I have figured out how to ensure my password has a number, uppercase and lowercase character. The password is being generated randomly from the string.printable function.

Here is the part of string.printable which I am using as accepted characters in my password:

0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ!"#$%&'()*+,-./:;<=>?@[\]^_`{|}~

I am trying to ensure that at least one of the character falls withing the range of indexes from ! to ~ which will ensure I have a special character in my password. Can someone help me with this.

Here is my code:

import random
import string


def password_generator(length):
    while True:
        my_password = ''
        for eachItem in range(length):
            my_password += string.printable[random.randint(0, len(string.printable) - 7)]
        if (any(x.isupper() for x in my_password) and any(x.islower() for x in my_password)
                and any(x.isdigit() for x in my_password)):
            return my_password


pass_length = int(input("Enter desired length of password: "))
print(password_generator(pass_length))

Answer 1

Easier:

• choose 1 random letter of each special group
• chose remaining letters of all possibible characters
• mix them up and join letters into a word

---

import random
import string 

def password_generator(length):

    allchar = string.printable  # that is about what your choice of characters is
    low = string.ascii_lowercase
    hig = string.ascii_uppercase
    spec = string.punctuation
    nums = string.digits

    pw = []

    # ensure that each group has at least 1 character of these groups
    pw.append(random.choice(low))
    pw.append(random.choice(hig))
    pw.append(random.choice(spec))
    pw.append(random.choice(nums)) 

    # and fill up with random from all groups
    pw.extend(random.choices(allchar, k=length-len(pw)))

    # mix the positions up
    random.shuffle(pw)
    # return as string
    return "".join(pw)

pass_length = int(input("Enter desired length of password: "))
for _ in range(10):
    print(password_generator(pass_length))

Output:

b]gDEK7:wM9_T__N:ugO
l1c2p3"rW)FB@=k]'1p~
9U=M'R3"Kbzqo/~8+Dr{
g`_w7tvL#Ulto&Q4Qi]"
O7(DttWffx4N7lr~B)h$
Azd2[HHTn:X!L\5^'\~`
%Sq}be2V<\eM^$$;)V@\
1}W{iBhV;u<D2@f5\m8P
E3vmhWxaWR'9hMeiU+1$

Answer 2

Your main propose is to generate passwords that contain special characters, not to check if these passwords contain special characters, but anyway, if you want to check it, just use the following code:

start = string.printable.find('!')
end = string.printable.find('~') + 1
special_chars = string.printable[start:end]
has_special_character = any(map(lambda c: c in chars, my_password))