通过匹配另一个数组中元素的属性从数组中删除元素

Question

I have two arrays:

var sessionsToDisplay : [SessionData]
var sessionsToDisplayTemp : [SessionData]

The SessionData class has a startTime Property. So, if the first sessionToDisplay array contains these items:

SessionData(startTime: "08:00", ...),
SessionData(startTime: "10:30", ...),
SessionData(startTime: "13:30", ...),
SessionData(startTime: "16:00", ...),

and the sessionsToDisplayTemp contains these:

SessionData(startTime: "06:30", ...),
SessionData(startTime: "16:00", ...),
SessionData(startTime: "12:30", ...),
SessionData(startTime: "15:30", ...),
SessionData(startTime: "08:00", ...),

I have to remove elements from sessionsToDisplayTemp , whose startTime is already there in the first array. So the result should be an array that has these elements:

SessionData(startTime: "06:30", ...),
SessionData(startTime: "12:30", ...),
SessionData(startTime: "15:30", ...),
SessionData(startTime: "08:00", ...),

Answer 1

You can use filter to check that an object isn't in the other array

let out = sessionsToDisplayTemp.filter {data in
    !sessionsToDisplay.contains {$0.startTime == data.startTime}
}

or if you want to remove them directly

sessionsToDisplayTemp.removeAll { data in
    sessionsToDisplay.contains {data.startTime == $0.startTime}
}