如何在python的for循环中仅打印某些条件

Question

so I am trying to make a for loop to print a certain condition but it keeps printing all the conditions. How do I make it stop and print the outcome I want? Here's what I have done till now:

f_list = ['nothing','You will get an A', 'You will learn to program','You are destined to become a master coder','May the force be with you \n',
    'Wow. You look like a programmer','The code is strong with this one','You will be testing your code often','Taco cat spelled backwards is taco cat','Your name will go down, down, down in history \n',
    'You will master python']

for luckyInt in range(1 ,len(f_list)):
    if (luckyInt == 1):
        print(f_list[1])
    elif luckyInt == 2:
        print(f_list[2])
    elif luckyInt == 3:
        print(f_list[3])
    elif luckyInt == 4:
        print(f_list[4])
    elif luckyInt == 5:
        print(f_list[5])
    elif luckyInt == 6:
        print(f_list[6])
    elif luckyInt == 7:
        print(f_list[7])
    elif luckyInt == 8:
        print(f_list[8])
    elif luckyInt == 9:
        print(f_list[9])
    elif luckyInt == 10:
        print(f_list[10])

Hi: The required output is this: Ooh-de-la-lay! Ooh-de-la-lay! Fortune tellers! Fortunes forecast! Lucky charms! Hmmm… the future is cloudy. What is your name?Leia Organa Oo-dee-lally! How exciting! How many fortunes do you wish to get today?5 Your total for today's session will be: 10.8455 I will tell your fortune. Leia Organa, enter your lucky integer number.300 Oops Leia Organa. I cannot tell your fortune until you enter a valid number.99 Leia Organa! This is your lucky day! Your name will go down, down, down in history I will tell your fortune. Leia Organa, enter your lucky integer number.-3 Oops Leia Organa. I cannot tell your fortune until you enter a valid number.3 Leia Organa! This is your lucky day! You are destined to become a master coder I will tell your fortune. Leia Organa, enter your lucky integer number.0 Leia Organa! This is your lucky day! You will master python I will tell your fortune. Leia Organa, enter your lucky integer number.-7 Oops Leia Organa. I cannot tell your fortune until you enter a valid number.7 Leia Organa! This is your lucky day! You will be testing your code often I will tell your fortune. Leia Organa, enter your lucky integer number.50000 Oops Leia Organa. I cannot tell your fortune until you enter a valid number.100 Leia Organa! This is your lucky day! You will master python You entered the following lucky numbers: [99, 3, 0, 7, 100] Process finished with exit code 0 :

Answer 1

我将打印所有内容，因为对于每个循环，它将输入一个条件。.第一个循环将打印1，第二个将打印2，依此类推..请提供所需输出样本的详细信息

Answer 2

I was able to fix your program and now it works great. It looks like you were close, but you need to give luckyInt a value and then compare that value to the index in a loop; rather than using luckInt as the index. I added a random number generator:

import random


def random_num(hi):
    lo = 0
    hi = hi-1
    return random.randint(lo, hi)


f_list = ['nothing', 'You will get an A', 'You will learn to program', 'You are 
destined to become a master coder \n',
'May the force be with you', 'Wow. You look like a programmer', 'The code is 
strong with this one \n',
'You will be testing your code often', 'Taco cat spelled backwards is taco cat \n',
'Your name will go down, down, down in history', 'You will master python']

luckyInt = random_num(len(f_list))

for i in range(len(f_list)):
    if luckyInt == i:
        print(f_list[i])

I hope this helps