如何重置计时器中的秒数

Question

Ho to reset seconds (it's "i" variable) when it's over 60? I tried to put it into the if but it didn't work.

SeekBar bar=findViewById(R.id.seekBar2);
final TextView textView=(TextView) findViewById(R.id.textView);


bar.setOnSeekBarChangeListener(new SeekBar.OnSeekBarChangeListener() {
    @Override
    public void onProgressChanged(SeekBar seekBar, int i, boolean b) {
        int minute=0;
        if(i>60) {
            minute++;
        }

        textView.setText(String.valueOf(minute)+":"+String.valueOf(i));

    }

    @Override
    public void onStartTrackingTouch(SeekBar seekBar) {

    }

    @Override
    public void onStopTrackingTouch(SeekBar seekBar) {

    }
});

Answer 1

Assuming you want the variable i to become 0 when it reaches 60,you just need to apply ' % ' modulus operator.

for ex:

i = i % 60

Answer 2

If you want to reset the SeekBar , simply use seekbar.setProgress(0);

Example

@Override
    public void onProgressChanged(SeekBar seekBar, int i, boolean b) {
        int minute=0;
        if(i>60) {
            seekbar.setProgress(0); //will reset the seekbar
            minute++;
        }

Answer 3

bar.setOnSeekBarChangeListener(new SeekBar.OnSeekBarChangeListener() {
@Override
public void onProgressChanged(SeekBar seekBar, int i, boolean b) {
    int minute=0;
    if(i>60) {
        minute++;
        i = 0;
    }

    textView.setText(String.valueOf(minute)+":"+String.valueOf(i));

}

@Override
public void onStartTrackingTouch(SeekBar seekBar) {

}

@Override
public void onStopTrackingTouch(SeekBar seekBar) {

}

});

Answer 4

You can calculate as

int minute = i/60;
int secs = i - (60 * minute);
textView.setText(String.valueOf(minute)+":"+String.valueOf(secs));