使用c#将xml元素提取为字符串

Question

I have an xml file, as per the sample below:

  <Header>
<CollectionDetails>
  <Collection></Collection>
  <Year>1415</Year>
  <FilePreparationDate></FilePreparationDate>
</CollectionDetails>
<Source>
  <ProtectiveMarking>PROTECT-PRIVATE</ProtectiveMarking>
  <UKPRN></UKPRN>
  <TransmissionType>A</TransmissionType>
  <SoftwareSupplier></SoftwareSupplier>
  <SoftwarePackage></SoftwarePackage>
  <Release>12.0.2.3</Release>
  <SerialNo>01</SerialNo>
  <DateTime>2015-10-22T17:01:51.800</DateTime>
</Source>

Within Header, I want to take out the "Year" value which is what i'm stuck on how to do. My current C# uses the below to read the file initially, but I can't get what I need from it so I can turn it into a string:

            XElement document = XElement.Load(str_FileLocation);
            var year = document.Element("Header");
            var year1 = year.Elements("CollectionDetails");
            var year2 = year1.Nodes("Year");

Answer 1

This is really straightforward with your XDocument :

XNamespace ns = "<default namespace here>"
var value = (string) doc.Descendants(ns + "Year").Single()

Where ns should be set to the default namespace as specified in the xmlns="..." attribute in an ancestor element (likely the document root).

I'd suggest reading the LINQ to XML guide for more explanation of how to use the API.

Answer 2

You can use following class to deserialize the xml into C# class object and then easily can access any property to get desired value

POC Code:

[XmlRoot(ElementName="CollectionDetails")]
public class CollectionDetails {
    [XmlElement(ElementName="Collection")]
    public string Collection { get; set; }
    [XmlElement(ElementName="Year")]
    public string Year { get; set; }
    [XmlElement(ElementName="FilePreparationDate")]
    public string FilePreparationDate { get; set; }
}

[XmlRoot(ElementName="Source")]
public class Source {
    [XmlElement(ElementName="ProtectiveMarking")]
    public string ProtectiveMarking { get; set; }
    [XmlElement(ElementName="UKPRN")]
    public string UKPRN { get; set; }
    [XmlElement(ElementName="TransmissionType")]
    public string TransmissionType { get; set; }
    [XmlElement(ElementName="SoftwareSupplier")]
    public string SoftwareSupplier { get; set; }
    [XmlElement(ElementName="SoftwarePackage")]
    public string SoftwarePackage { get; set; }
    [XmlElement(ElementName="Release")]
    public string Release { get; set; }
    [XmlElement(ElementName="SerialNo")]
    public string SerialNo { get; set; }
    [XmlElement(ElementName="DateTime")]
    public string DateTime { get; set; }
}

[XmlRoot(ElementName="Header")]
public class Header {
    [XmlElement(ElementName="CollectionDetails")]
    public CollectionDetails CollectionDetails { get; set; }
    [XmlElement(ElementName="Source")]
    public Source Source { get; set; }
}

Sample code:

XmlSerializer serializer = new XmlSerializer(typeof(Header));
StreamReader reader = new StreamReader(path);
var header = (Header)serializer.Deserialize(reader);
reader.Close();
//use the header object to access your data

Update Here's another way using xpath:

using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Xml.XPath;

namespace ConsoleApp1
{
    class Program
    {
        static void Main(string[] args)
        {
            XPathNavigator nav;
            XPathDocument docNav;
            string xPath;

            docNav = new XPathDocument(AppDomain.CurrentDomain.BaseDirectory + "test.xml");
            nav = docNav.CreateNavigator();
            xPath = "/Header/CollectionDetails/Year/text()";

            string value = nav.SelectSingleNode(xPath).Value;
            Console.WriteLine(value);
        }
    }
}