Python-从dict行打印

Question

I'm a beginner at python and I'm experiencing difficulties printing nicely. I made a program that stores names and prices in dictionary. ( eg : {"PERSON_1":"50","PERSON_2":"75","PERSON_WITH_EXTREMELY_LONG_NAME":"80"} Now the problem is that I want to be able to print the keys and their supposed values in a nice scheme. I used the code:

 for i in eter.eters:
        print(i + "\t | \t" + str(eter.eters[i]))

with eter.eters being my dictionary. The problem is that some names are a lot longer than others, so the tabs don't align. As well as my header: "Names" | "Price" should be aligned with the information below. I've already looked up some solutions, but I don't really understand the ones I found. Desired outcome:

**********************************************************************
               De mensen die blijven eten zijn:
**********************************************************************
Naam                            |      bedrag
----------------------------------------------------------------------
PERSON 1                        |      50
PERSON 2                        |      75
PERSON WITH EXTREMELY LONG NAME |      80
**********************************************************************

Answer 1

try this:

given eter.eters is your dictionary

print('%-35s | %6s' % ('Names', 'Price')) # align to the left

for k in eter:
    print('%-35s | %6s' % (k,eter[k]))

or

print("{0:<35}".format('Name')+'|'+"{0:>6}".format('Price'))

for k in eter:
    print("{0:<35}".format(k)+'|'+"{0:>6}".format(eter.eters[k]))

Answer 2

You can try to get all of the names and find the maximum length of it. Then show every name with special padding instead of tabulator ( \\t ). This code should explain:

>>> d={"Marius":"50","John":"75"}
>>> d
{'Marius': '50', 'John': '75'}
>>> for i in d:
...  print(i)
... 
Marius
John
>>> d = {"Marius":"50","John":"75"}
>>> m = 0
>>> for i in d:
...  m = max(m, len(i))
... 
>>> m
6 # now we know the place reserved for Name column should be 6 chars width
>>> for i in d:
...  print( i + (m-len(i))*' ' , d[i]) # so add to the name space char that fit this 6 chars space
... 
Marius 50
John   75