[英]the condition in my while loop doesn't seem right?
trying to write a program that casts a die 3 times and once you get 3 6s in a row it prints out how many tries it took. 尝试编写一个将骰子投放3次的程序,一旦连续获得3个6s,它就会打印出需要尝试的次数。 having a problem at the end of the code, the diff between ||
在代码末尾有问题,||之间的差异 and &&, seems like it's the opposite, have a look...
和&&似乎相反,看看...
package javaapplication12;
import java.util.*;
public class JavaApplication12 {
public static void main(String[] args) {
Random rand = new Random();
// this should try to cast a die 3 times and keep doing that until we get 3 6s in a row and counter
// how many tries it takes to get that.
int array[] = new int[3]; // creating 3 places for castin our die 3 times in a row
int counter1 = 0; // creating a counter to track each time we try to cast 3 die ( 3 cast = 1 try)
do{
counter1++;
System.out.println("try " + counter1); // prints out counter in the beginning of every try.
for (int counter = 0; counter < array.length; counter++ ){
array[counter]=(rand.nextInt(6)+1); // a loop that fills the array with random numbers from 1-6
}
for(int x: array)
{System.out.println(x);} // this is for our own to check if we have 3 6s in a row,
// prints out all the numbers in out array
}
//so this is the I'veusing part, i've written 3 scenarios that can be written for the condtion in our
// do- while loop...
while (array[0]+array[1]+array[2] != 18); // this works just fine.
while (array[0] !=6 || array[1] != 6 || array[2] != 6); // imo this should not work but surprisingly it does
while (array[0] !=6 && array[1] != 6 && array[2] != 6); // this should work, but it doesnt.
}
}
I believe your confusion comes forth from De Morgan's laws of negation . 我相信您的困惑来自De Morgan的定律 。 Basically, when you have a negation of a group of conditions, you should change
&&
by ||
基本上,当您否定一组条件时,应通过
||
更改&&
。 and vice versa when you negate the individual conditions. 否定各个条件时,反之亦然。
Or simply put: 或简单地说:
!(A && B) == !A || !B
!(A || B) == !A && !B
In you case, you want to do this: 在这种情况下,您想这样做:
!(array[0] == 6 && array[1] == 6 && array[2] == 6)
aka. 又名。 "while it's not true that the first is 6 AND the second is 6 AND the third is six"
“虽然第一个是6,第二个是6,第三个是6,这不是真的”
Due to the above law, in order to bring the !
由于上述法律,为了带来
!
inside, you need to change &&
for ||
在里面,您需要更改
&&
为||
, resulting in , 导致
!(array[0] == 6) || !(array[1] == 6) || !(array[2] == 6)
Simplified to 简化为
array[0] != 6 || array[1] != 6 || array[2] != 6
Your first condition is: The sum is not 18, so indeed it should work correctly. 您的第一个条件是:总和不是18,因此确实应该正确运行。
The second condition is: At least one die is not 6, so it should also work correctly. 第二个条件是:至少一个骰子不是6,所以它也应该正常工作。
Your last condition: No die is 6, so it will break even if a single die rolls 6, so it makes sense that it does not work. 您的最后一个条件:没有骰子是6,所以即使单个骰子滚动6,它也将断裂,因此这是行不通的。
UPDATE: The AND (&&) means that both sides of the arguments must be true for the output to be true, the OR (||) means that one side of the arguments needs to be true for the outcome to be true. 更新:AND(&&)表示参数的两面都必须为真,才能使输出为真; OR(||)表示参数的一面必须为真,以使结果为真。
You need to revisit the basic operations of boolean algebra . 您需要重新研究布尔代数的基本运算。
That is how it was supposed to work. 那应该是这样的。 This one:
这个:
do{
}while(array[0] !=6 && array[1] != 6 && array[2] != 6)
mean that as long as the condition is true the loop will continue. 意味着只要条件为真,循环就会继续。 Putting it the other way - if either part is evaluated to false then the loop will stop.
换句话说,如果将任一部分评估为false,则循环将停止。 So if
array[0]==6
then the loop will break. 因此,如果
array[0]==6
则循环将中断。
while (array[0] !=6 || array[1] != 6 || array[2] != 6);
This works fine because it means: "while one of the three attempts is not 6" 这很好,因为它的意思是:“虽然三个尝试之一不是6”
so the exit condition is: "all the die are 6" 因此退出条件为:“所有骰子均为6”
while (array[0] !=6 && array[1] != 6 && array[2] != 6);
This doesn't works because it means: "while neither of the three attempts is 6" 这是行不通的,因为它的意思是:“虽然三个尝试都不是6”
so the exit condition is: "at least one die is 6" 因此退出条件为:“至少一个骰子为6”
while (array[0]+array[1]+array[2] != 18);
This works fine because it means: "the die result sum is 18" 之所以可以正常工作,是因为它意味着:“模具结果总和为18”
so the exit condition is: "all the die are 6" (because it's the only way to sum 18) 因此退出条件为:“所有骰子均为6”(因为这是加总18的唯一方法)
Generally: 通常:
do{
something....
}while(some condition is true);
If you want to express it with the '&&' operator 如果要使用“ &&”运算符表示
do{
something....
}
while (!(array[0] == 6 && array[1] == 6 && array[2] == 6));
meaning 含义
do {
something...
}while(the expression every element in the array is equal to 6 is false);
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