Swagger UI 3.19.4（Swagger 2.0）查询参数选择

Question

I have Swagger UI 3.19.4 and I want to create REST requests like following:

GET https://<host>/<path>?select=*

It means that I want to add query parameter select=* in each get request that will be sent from Swagger UI .

How can I do that?

Answer 1

My solution is to use requestInterceptor

SwaggerUiBundle({
...,
requestInterceptor: (request) => {
  uri = new URI(request.uri);
  uri.selectParams.append("select", "*");
  request.uri = uri.toString();
  //code
  return request;
}
})

I decided to use requestInterceptor, because it is official way to modify requests from SwaggerUI https://swagger.io/docs/open-source-tools/swagger-ui/usage/configuration/ . Also to modify URL you can use standard class URL (JavaScript).