[英]Custom test source set with Gradle Kotlin DSL and Intellij
My project is using Gradle with Kotlin DSL for building.我的项目使用 Gradle 和 Kotlin DSL 进行构建。 I now want to add a custom sourceset used for testing.
我现在想添加一个用于测试的自定义源集。 The relevant code looks as follows:
相关代码如下所示:
java {
sourceSets.create("systemTest") {
java.srcDir("src/system-test/java")
resources.srcDir("src/system-test/resources")
}
}
By using that, I get another module in Intellij, which is treated as source module.通过使用它,我在 Intellij 中获得了另一个模块,它被视为源模块。 I also tried the following to mark it as test module:
我还尝试了以下将其标记为测试模块:
idea.module {
testSourceDirs.addAll(project.sourceSets.getByName("systemTest").java.srcDirs)
testSourceDirs.addAll(project.sourceSets.getByName("systemTest").resources.srcDirs)
}
However, if I then do a ./gradlew clean idea
and open the project using the generated files (normally I import my projects from Gradle), the system-test folder isn't treated as source module at all.但是,如果我然后执行
./gradlew clean idea
并使用生成的文件打开项目(通常我从 Gradle 导入我的项目),则 system-test 文件夹根本不会被视为源模块。
Anyone having experience with declaring a custom sourceset with Kotlin DSL AND marking it as test module?任何有使用 Kotlin DSL 声明自定义源集并将其标记为测试模块的经验?
EDIT : I now created a sample Gradle project using Groovy and there it worked without problems with using the following code (which I guess is just the groovy version of my statements above):编辑:我现在使用 Groovy 创建了一个示例 Gradle 项目,并且在使用以下代码时它没有问题(我猜这只是我上面语句的 groovy 版本):
sourceSets {
systemTest {
java {
compileClasspath += main.output + test.output
runtimeClasspath += main.output + test.output
srcDir file('src/system-test/java')
}
resources.srcDir file('src/system-test/resources')
}
}
idea {
module {
testSourceDirs += project.sourceSets.systemTest.java.srcDirs
testSourceDirs += project.sourceSets.systemTest.resources.srcDirs
}
}
So either I am getting the transformation to Kotlin DSL wrong or it is a bug on the Intellij side.因此,要么是我错误地转换为 Kotlin DSL,要么是 Intellij 方面的错误。
Seems like I got the Kotlin transformation wrong, it should be 似乎我弄错了Kotlin转换,应该是
idea.module {
val testSources = testSourceDirs
testSources.addAll(project.sourceSets.getByName("systemTest").java.srcDirs)
testSources.addAll(project.sourceSets.getByName("systemTest").resources.srcDirs)
testSourceDirs = testSources
}
Using this snippet, the testSourceDirs
set is changed and the relevant sourceset marked as test module. 使用此代码段,更改
testSourceDirs
集,并将相关的testSourceDirs
集标记为测试模块。
Another way to do the same:另一种方法来做同样的事情:
testSourceDirs = testSourceDirs.plus(sourceSets["integrationTest"].java.srcDirs)
testResourceDirs = testResourceDirs.plus(sourceSets["integrationTest"].resources.srcDirs)
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