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PHP链式类方法与其他类合并

[英]PHP chained class methods merged with other classes

I start with an example. 我从一个例子开始。

Mold class 模具类

<?php
class Mold {
  public $current;

  function merge($first, $second) {
    $this->current = $first . $second;
    return $this;
  }

  function phone() {
    $this->current = '<a href="tel:' . $this->current . '">' . $this->current . '</a>';
    return $this;
  }

  function __toString() {
    return $this->current;
  }
}

function mold() {
  return new Mold();
}

In action 在行动

This works as expected. 这按预期工作。

echo mold()->merge('sada', 'asdsa')->phone();

Problem 问题

I have one or more classes with methods that wants to be available as well. 我有一个或多个类,它们的方法也希望可以使用。

Plugin class 插件类

class MyPlugin {
  function link() {
    // Code
  }

  function currency($number) {
    // Code
  }
}
class MyPlugin2 {
  // Other methods
}

Dream code 梦代码

The exact change of events below may not make any sense. 以下事件的确切变化可能没有任何意义。 Anyway, what I intend to do is the following. 无论如何,我打算做以下事情。

echo mold()->merge('sada', 'asdsa')->currency(45)-link();
  • Call mold() which creates a new instance of the Mold class. 调用mold()创建一个新的Mold类实例。
  • Chain merge() which is used from the Mold class. Mold类使用的chain merge()
  • currency() or link() method does not exist in the Mold class. Mold类中不存在currency()link()方法。 Instead they should be loaded from one of the plugins. 而是应从其中一个插件加载它们。

In conclusion 结论

  • I know I can extend a class but it does not really solve the problem because there can be more than one plugin classes. 我知道我可以扩展一个类,但是它不能真正解决问题,因为可以有多个插件类。
  • I know I can create instances of the plugin classes, but they somehow need to be aware by the Mold class. 我知道我可以创建插件类的实例,但是它们需要以某种方式由Mold类注意。
  • Append methods to a class comes to mind as well as merge classes. 将方法追加到类以及合并类都放在脑海中。

Technically you could use __call() for this. 从技术上讲,您可以使用__call() Your "main" class could contain/track a set of plugin instances and any unknown method call could be looked up and delegated, if available in a plugin. 您的“主”类可以包含/跟踪一组插件实例,并且可以查找和委托任何未知的方法调用(如果在插件中可用)。

I wouldn't recommend this though. 我不会推荐这个。 Fluent APIs are often brittle and can get inconvenient even with one class. 流利的API通常很脆弱,即使只有类也可能带来不便。 Involving multiple classes in fluent calls might quickly to add up to a confusing mess. 使多个类参与流利的调用可能很快就会造成混乱。 A mess which even IDE can't help you (or another person working with code) with since it has no clue about all the magic happening. 混乱,甚至IDE也无法帮助您(或其他使用代码的人),因为它无法掌握所有发生的魔术。

I would highly recommend to look into alternative patterns for an API like this. 我强烈建议您研究此类API的替代模式。

A concept that you might try to apply is the Composition Over Inheritance . 您可以尝试应用的概念是继承上的合成

A solution could be to compose your current Mold object and pass the two plugins instances so that it could use them on its methods, like so: 一个解决方案可能是组成当前的Mold对象并传递两个插件实例,以便它可以在其方法上使用它们,如下所示:

<?php
class Mold {
  public $current;

  public function __construct(Plugin1 $plugin1, Plugin2 $plugin2) {
      $this->plugin1 = $plugin1;
      $this->plugin2 = $plugin2;
  }

  public function merge($first, $second) {
    $this->current = $first . $second;
    return $this;
  }

  public function phone() {
    $this->current = '<a href="tel:' . $this->current . '">' . $this->current . '</a>';
    return $this;
  }

  public function __toString() {
    return $this->current;
  }

  public function link() {
      $this->plugin1->link();
      return $this;
  }
}

function mold() {
  return new Mold(new Plugin1(), new Plugin2());
}

Another solution could be to create a MoldHandler class of some sort, which has a Mold object as a property together with the other plugins, which could be used inside of this directly. 另一个解决方案是创建某种MoldHandler类,该类将Mold对象作为属性与其他插件一起使用,可以直接在其中使用。

public class MoldHanlder {

    protected $mold;
    protected $plugin1;
    protected $plugin2;

    public function __contruct($mold, $plugin1, $plugin2) {
        $this->mold    = $mold;
        $this->plugin1 = $plugin1;
        $this->plugin2 = $plugin2;
    }

    public function merge() {
        $this->mold = $this->mold->merge();
        return $this;
    }

    public function link() {
        $foo = $this->plugin1->method();

        return $this;
    }

    ...
}

You could also just instantiate the classes inside the construct , but if you are planning about writing unit tests, dependency injection is the way to go 您也可以只实例化construct的类,但是如果您打算编写单元测试,则依赖注入是解决之道

I think that the first approach is way better because you avoid yourself to re-write some code of the Mold class, which is unnecessary 我认为第一种方法更好,因为您避免自己重新编写Mold类的一些代码,这是不必要的

NB this is a really raw solution proposed just to let you better understand the idea I would opt for cheers 注意,这是一个非常原始的解决方案,只是为了让您更好地理解我会选择的想法

Interesting ideas. 有趣的想法。

The one that solves the problem like I had in my mind was to use traits like @vivek_23 suggested in a comment. 解决我所想到的问题的一种方法是使用注释中建议的@ vivek_23之类的特征

Here is a complete example of how it works 这是工作原理的完整示例

<?php
// Core methods
class MoldCore {
  public $current;

  function merge($first, $second) {
    $this->current = $first . $second;
    return $this;
  }

  function phone() {
    $this->current = '<a href="tel:' . $this->current . '">' . $this->current . '</a>';
    return $this;
  }

  function __toString() {
    return $this->current;
  }
}

// Plugin 1
trait Plugin1 {
  public function yaay() {
    $this->current .= ' Plugin1 yaay';
    return $this;
  }
}

// Plugin 2
trait Plugin2 {
  public function hello() {
    $this->current = str_replace('Plugin1', 'Modified', $this->current);
    return $this;
  }

  public function world() {
    $this->current .= ' Plugin2 world';
    return $this;
  }
}

// Glue plugins with MoldCore
class Mold extends MoldCore {
  use Plugin1, Plugin2;
}

$mold = new Mold();
echo $mold->merge('sada', 'asdsa')->phone()->yaay()->hello();

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