[英]How to include the values from two tables in the same column
I have the following query: 我有以下查询:
select
t1.x,
t2.y
from table1 t1
join table2 t2
on t1.x = t2.x
which is producing the following results: 产生以下结果:
x y1
x y2
x y3
I, however, want it to produce the following, where the value from t1.x is also in the second column: 但是,我希望它产生以下内容,其中t1.x中的值也在第二列中:
x x
x y1
x y2
x y3
Is there an easy way to do this? 是否有捷径可寻? I'm trying to achieve this in PostgreSQL but I would also be interested in any solution in MySQL.
我正在尝试在PostgreSQL中实现这一目标,但我也对MySQL中的任何解决方案感兴趣。
Thanks in advance! 提前致谢!
You seem to want: 您似乎想要:
select t1.x, t1.x as y
from table1 t1
union all
select t2.x, t2.y
from table2 t2;
The join
is only needed if you want to filter (or multiply) the rows, based on x
being in both tables. 仅当您要基于两个表中的
x
来过滤(或相乘)行时才需要join
。
I am not sure if that is what you need. 我不确定这是否是您所需要的。 But I suspect you just need
LEFT JOIN
with some tweak: 但是我怀疑您只需要通过一些调整就可以
LEFT JOIN
:
SELECT
t1.x,
COALESCE(t2.y, t1.x)
FROM table1 t1
LEFT JOIN table2 t2
ON t1.x = t2.x
You can use UNION: 您可以使用UNION:
select
x,
x as y
from table1
union
select
t1.x,
t2.y
from table1 t1
join table2 t2
on t1.x = t2.x
order by x
or 要么
select
t1.x,
t1.x
from table1 t1
join table2 t2
on t1.x = t2.x
union
select
t1.x,
t2.y
from table1 t1
join table2 t2
on t1.x = t2.x
order by x
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