JS通过另一个对象数组过滤对象数组

Question

I have three arrays of objects:

const names = [
  { value: "Time" },
  { value: "Angle" },
  { value: "Speed" },
  { value: "Mass" }
];

const params = [
  { name: "Time", value: "s" },
  { name: "Time", value: "h" },
  { name: "Time", value: "m" },
  { name: "Angle", value: "rad" },
  { name: "Angle", value: "grade" }
];

const selected = [
  { id: 1, name: "Time", param: "s" },
  { id: 2, name: "Time", param: "h" },
  { id: 3, name: "Time", param: "m" },
  { id: 4, name: "Angle", param: "grade" },
  { id: 5, name: "Speed", param: null }
];

I need new names array without items that:

• have been selected with all possible params
• if given name does not have param possible it can bo selected only once

in this case my expected output should be

    const expected = [
      { value: "Angle" }, 
      { value: "Mass" }
    ]

Answer 1

You could filter by

• not having some value with param null and
• not having equal length of the filterd params and selected items and having a length.

 const names = [{ value: "Time" }, { value: "Angle" }, { value: "Speed" }, { value: "Mass" }], params = [{ name: "Time", value: "s" }, { name: "Time", value: "h" }, { name: "Time", value: "m" }, { name: "Angle", value: "rad" }, { name: "Angle", value: "grade" }], selected = [ { id: 1, name: "Time", param: "s" }, { id: 2, name: "Time", param: "h" }, { id: 3, name: "Time", param: "m" }, { id: 4, name: "Angle", param: "grade" }, { id: 5, name: "Speed", param: null }], result = names.filter(({ value }) => { const check = ({ name }) => name === value, pl = params.filter(check).length, sl = selected.filter(check).length; return !selected.some(o => o.name === value && o.param === null) && !(pl === sl && pl); }); console.log(result);