在python中获取'+'字符之前的字符串内容

Question

INPUT:

s = 'Coated tablet + ALFUZOSIN HYDROCHLORIDE, Film-coated tablet + ALFUZOSIN HYDROCHLORIDE, Modified-release tablet + ALFUZOSIN HYDROCHLORIDE, Prolonged-release tablet + ALFUZOSIN HYDROCHLORIDE'

EXPECTED OUTPUT:

s = 'Coated tablet, Film-coated tablet, Modified-release tablet, Prolonged-release tablet'

For each string like this, how do I get the necessary output in Python so that all elements after the + doesn't come.

Answer 1

Do split on , and then on + and fetch item at index 0

', '.join([i.split("+")[0].strip() for i in s.split(",")])

Output

'Coated tablet, Film-coated tablet, Modified-release tablet, Prolonged-release tablet'

Answer 2

Using regular expressions,

It removes from + until it runs out of characters that aren't a comma

import re
s = 'Coated tablet + ALFUZOSIN HYDROCHLORIDE, Film-coated tablet + ALFUZOSIN HYDROCHLORIDE, Modified-release tablet + ALFUZOSIN HYDROCHLORIDE, Prolonged-release tablet + ALFUZOSIN HYDROCHLORIDE'

re.sub(" [+] [^,]+","",s)

Answer 3

Using regular expression:

import re

old_s = 'Coated tablet + ALFUZOSIN HYDROCHLORIDE, Film-coated tablet + ALFUZOSIN HYDROCHLORIDE, Modified-release tablet + ALFUZOSIN HYDROCHLORIDE, Prolonged-release tablet + ALFUZOSIN HYDROCHLORIDE'
new_s = re.sub(r'\s\+.*?, | \+.*?$', ',', s)[:-1]

print(new_s)
>>> 'Coated tablet, Film-coated tablet, Modified-release tablet, Prolonged-release tablet'

On the left hand of the pipe \\s indicates white space, \\+.*?, looks for everything between a + and a , , on the right side, you're going for the end case where there is no comma, using $ instead.

[:-1] because all matches are replaced by a comma, however, you don't want the comma at the end of your string.