如何返回字典中与最大值对应的键？

Question

In this code I calculated the average score for each student and return it in a dictionary to create a dictionary with a two-dimensional array:

def bestAverage(inputDict):
    dic = {}
    for i in inputDict:
        if i[0] in dic.keys():
            dic[i[0]].append(int(i[1]))
        else:
            dic[i[0]] = [int(i[1])]
    totle_score = 0
    print(dic)
    for key, value, in dic.items():
        for c in value:
         totle_score += int(c)
        Q = len(value)
        avrage = totle_score / Q
        dic[key]= [avrage]
    print(dic)

OUTCOME:

{'Diane': [35.0], 'Bion': [95.0], 'Jack': [125.0]}

NOW, how to return the name with the highest average score?

Answer 1

dict = {'Diane': [35.0], 'Bion': [95.0], 'Jack': [125.0]}

highest_scorer = max(dict, key=dict.get)
highest_score = dict[highest_scorer]

Reference https://docs.python.org/3/library/functions.html#max

You can also try max(iterable) , but I prefer using max(iterable, *args) .

Answer 2

max_score = max(d.values())[0]
name_max = [k for k,v in d.items() if v[0]==max_score]

Answer 3

import operator
max(dic.items(), key=operator.itemgetter(1))[0]

you can also use

max(dic, key=dic.get)