[英]How can I define a type that “implements” an interface?
Classes can implement interfaces: 类可以实现接口:
interface ClockInterface {
currentTime: Date;
}
class Clock implements ClockInterface {
currentTime: Date;
constructor(h: number, m: number) { }
}
How can I define a type that "implements" an interface? 如何定义“实现”接口的类型? I don't understand why the following does not work, as it looks completely reasonable to me: 我不明白以下原因为何不起作用,因为在我看来,这完全合理:
type DigitalClock implements ClockInterface = {
currentTime: Date;
somethingDigital: any;
}
Just use 只需使用
type DigitalClock = ClockInterface & {
somethingDigital: any;
}
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