[英]SQL Server: matching two tables and results in the order of proper column
I have two tables JOB
and EMP
;我有两个表
JOB
和EMP
; structure and values are like this:结构和值是这样的:
CREATE TABLE JOB
(
JOBID SMALLINT UNIQUE NOT NULL,
JOBNAME CHAR(15)
);
CREATE TABLE EMP
(
EMPID SMALLINT,
JOBID SMALLINT,
SAL SMALLINT,
CITYID SMALLINT,
YEAR SMALLINT,
STATUS CHAR(1)
);
INSERT INTO JOB(JOBID, JOBNAME)
VALUES (1, 'DEVELOPMENT'),
(2, 'DEVELOPMENT'),
(3, 'TESTING'),
(4, 'TESTING'),
(7, 'TESTING'),
(9, 'RESEARCH'),
(8, 'HR');
INSERT INTO EMP (EMPID , JOBID, SAL, CITYID, YEAR, STATUS)
VALUES (100, 1, 1000, 10, 2015, 'A'),
(200, 2, 2000, 10, 2015, 'A'),
(300, 1, 2500, 20, 2015, 'A'),
(400, 3, 1000, 10, 2016, 'A'),
(500, 6, 3000, 10, 2015, 'E'),
(600, 8, 1000, 30, 2015, 'A'),
(700, 8, 2000, 10, 2015, 'E'),
(800, 9, 1500, 10, 2015, 'A');
I want to display all jobname count and avg salaries;我想显示所有工作名称计数和平均工资; for the jobname if jobid's not exists then display 0
对于作业名称,如果作业 ID 不存在,则显示 0
For the given input cityid
, YEAR
and STATUS
( Emp
table), take all jobid
for each jobname
(from job
table ) and match in Emp
table, if exists display count
(count of jobid
present in Emp
table) and avgsal else 0
for count
and avgsal
.对于给定的输入
cityid
, YEAR
和STATUS
( Emp
表),采取所有jobid
为每个jobname
(从job
表)和匹配Emp
表,如果存在显示count
(计数的jobid
存在于Emp
表)和avgsal else 0
为count
和avgsal
。 And Sal
is calculated based on Status
. Sal
是根据Status
计算的。 If Status
is 'A' Sal goes to Status-A-Sal else Status-E-Sal
.如果
Status
是 'A' Sal 转到Status-A-Sal else Status-E-Sal
。 And for each matched ie non zero record put 'X' in another field对于每个匹配的非零记录,将“X”放在另一个字段中
Output should be like this for Cityid
's 10 and 20 year 2015. Results should be displayed first for Status
'A' and then Status
'E'.对于
Cityid
2015 年的第 10 年和第 20 年,输出应如下所示。应首先显示Status
“A”的结果,然后显示Status
“E”。 Added status type field in result .在 result 中添加了状态类型字段。
Cityid Status-type jobname count STATUS sal
--------------------------------------------------------------
10 STATUSA development 2 X 1500
10 STATUSA TESTING 0 0
10 STATUSA RESEARCH 1 X 1500
10 STATUSA HR 0 0
10 total 3 0
10 STATUSE development 0 0
10 STATUSE TESTING 0 0
10 STATUSE RESEARCH 0 0
10 STATUSE HR 1 X 2000
10 total 1 2000
20 STATUSA development 1 X 2500
20 STATUSA TESTING 0 0
20 STATUSA RESEARCH 0 0
20 STATUSA HR 0 0
20 total 1 2500
20 STATUSE development 0 0
20 STATUSE TESTING 0 0
20 STATUSE RESEARCH 0 0
20 STATUSE HR 0 0
20 total 0 0
How to bring the results one status after another ?如何带来一个又一个的结果?
I've tried like this but its throwing我试过这样但它投掷
SELECT C.CITYID AS CITYID,
CASE WHEN P.STATUS ='A' THEN 'STATUSA' ELSE 'STATUSE' END AS STATUS_TYPE ,
COALESCE(J.JOBNAME, 'TOTAL') AS JOBNAME,
COUNT(CASE WHEN P.STATUS ='A' THEN P.CITYID END ) AS COUNT ,
COALESCE(AVG(CAST(CASE WHEN P.STATUS = 'A' THEN P.SAL END AS DECIMAL(13,2)))/12 , 0) AS "AVG SAL",
COUNT(CASE WHEN P.STATUS ='E' THEN P.CITYID END ) AS COUNT ,
COALESCE(AVG(CAST(CASE WHEN P.STATUS = 'E' THEN P.SAL END AS DECIMAL(13,2)))/12 , 0) AS "AVG SAL"
FROM JOB1 J
CROSS JOIN
(SELECT DISTINCT CITYID
FROM EMP1 B WHERE CITYID = 10
) C
LEFT JOIN EMP1 P ON P.JOBID = J.JOBID
AND P.CITYID = C.CITYID and
YEAR = 2015
GROUP BY ROLLUP(C.CITYID, J.JOBNAME );
ERROR: Column 'EMP1.STATUS' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.
错误:列“EMP1.STATUS”在选择列表中无效,因为它不包含在聚合函数或 GROUP BY 子句中。
IF OBJECT_ID('tempdb..#JOB') IS NOT NULL
DROP TABLE #JOB
CREATE TABLE #JOB
(
JOBID SMALLINT UNIQUE NOT NULL,
JOBNAME CHAR(15)
);
IF OBJECT_ID('tempdb..#EMP') IS NOT NULL
DROP TABLE #EMP
CREATE TABLE #EMP
(
EMPID SMALLINT,
JOBID SMALLINT,
SAL SMALLINT,
CITYID SMALLINT,
YEAR SMALLINT,
STATUS CHAR(1)
);
INSERT INTO #JOB(JOBID, JOBNAME)
VALUES (1, 'DEVELOPMENT'),
(2, 'DEVELOPMENT'),
(3, 'TESTING'),
(4, 'TESTING'),
(7, 'TESTING'),
(9, 'RESEARCH'),
(8, 'HR');
INSERT INTO #EMP (EMPID , JOBID, SAL, CITYID, YEAR, STATUS)
VALUES (100, 1, 1000, 10, 2015, 'A'),
(200, 2, 2000, 10, 2015, 'A'),
(300, 1, 2500, 20, 2015, 'A'),
(400, 3, 1000, 10, 2016, 'A'),
(500, 6, 3000, 10, 2015, 'E'),
(600, 8, 1000, 30, 2015, 'A'),
(700, 8, 2000, 10, 2015, 'E'),
(800, 9, 1500, 10, 2015, 'A');
;with cteJobDict as (
select
distinct
j.JOBNAME
from
#JOB j
)
,cteStatusDict as(
select
distinct STATUS
from
#EMP e
),cteCityDict as (
select
distinct CITYID
from
#EMP
)
,cteJobStatusCityMatrix as(
select
*
from
cteJobDict
cross apply cteStatusDict
cross apply cteCityDict
)
,cteEmpWithJobName as (
select
e.*
,j.JOBNAME
from
#EMP e
join #JOB j on j.JOBID=e.JOBID
), cteData as (
SELECT
m.CITYID
,CASE WHEN m.STATUS ='A' THEN 'STATUSA' ELSE 'STATUSE' end as [Status-type]
,CASE WHEN m.STATUS ='A' THEN 1 ELSE 3 end as [Status-order]
,m.JOBNAME
,count(distinct e.EMPID) count
,iif(count(distinct e.EMPID)>0,'X','') status
,isnull(avg(e.sal),0) sal
FROM
cteJobStatusCityMatrix m
left join cteEmpWithJobName e on e.CITYID=m.CITYID and e.STATUS=m.STATUS and e.JOBNAME=m.JOBNAME and e.YEAR=2015
where
m.CITYID in (10,20)
group by
m.CITYID
,m.STATUS
,m.JOBNAME
union
SELECT
m.CITYID
,'total' as [Status-type]
,CASE WHEN m.STATUS ='A' THEN 2 ELSE 4 end as [Status-order]
,null
,count(distinct e.EMPID) count
,iif(count(distinct e.EMPID)>0,'X','') status
,isnull(avg(e.sal),0) sal
FROM
cteJobStatusCityMatrix m
left join cteEmpWithJobName e
on e.CITYID=m.CITYID
and e.STATUS=m.STATUS
and e.JOBNAME=m.JOBNAME
and e.YEAR=2015 -- here goes year
where
m.CITYID in (10,20) -- here goes cityid
group by
m.CITYID
,m.STATUS)
select
CITYID
,[Status-type]
,JOBNAME
,count
,status
,sal
from
cteData
order by
CITYID
,[Status-order]
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