硒（如果在屏幕上定位无法找到元素）

Question

I'll keep this question simple: I have an if statement:

if self.driver.find_element_by_xpath('//*[contains(@id, "mission_countdown")]'):

And i get this error:

selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//*[contains(@id, "mission_countdown")]"}

Why do I get this? I mean its an if statement, IF its on screen

Thanks for helping

Answer 1

find_element_by_xpath can return

• WebElement (if any found)
• NoSuchElementException (if not found)

If you're searching for the output that can be evaluated as boolean to use in if / else block, try find_elements :

if self.driver.find_elements_by_xpath('//*[contains(@id, "mission_countdown")]'):
    print('At least one element was found')
else:
    print('No elements found')

Answer 2

The code below is an example. It explicitly waits and moves to the object element you want to find. Adding in the try will throw the except error message if it does not find the element

from selenium import webdriver
from selenium.webdriver.common.action_chains import ActionChains
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
#--------
# all other code to begin scraping here
#--------

try:
    if self.driver.find_element_by_xpath('//*[contains(@id, "mission_countdown")]'):
       print("found this button")

    elif: 
        print("not found trying new button ")
        self.driver.find_element_by_xpath("xpath here")

except:
    print("ERROR MESSAGE: NO ELEMENT FOUND")

I hope this helps

Answer 3

Use try...catch block.If it is not their it will go to catch block.Let me know if this work for you.

try:
    if self.driver.find_element_by_xpath('//*[contains(@id, "mission_countdown")]'):
        print('found')
except:
    print('Not found')