如何编写一个SQL查询来检索同一列上具有2个条件的所有行

Question

How to write a SQL Query which retrieves all the rows with 2 condition on the same column?

I got a table with a column called type. What I want to do is to list up all type of value "name". But the type column also has a value called text. So what I want to do is to list up all type of names, that has type text value.

How can I achieve this?

ID     Type     Value
1      Name    Name1
1      Text    "Hello"
2      Text    "Hello test"
2      Name    Name2
3      Name    Name3
4      Name    Name4
5      Name    Name5

I only want to return name value that has a type text. The table has two types, what I want to do it to only return all of the type "Name" which has a type text

Expected result:

ID     Type     Value
1      Name    Name1
2      Name    Name2

Because these two are the only one with type "text" with a value.

Answer 1

Is this what you want?

Select * from
(
select a.* from tbl a join tbl b
on a.ID = b.ID
where
a.Type = 'Name' and b.Type = 'Text'
) tb
where tb.Type = 'Name'

Answer 2

Do a self join:

select t1.*
from tablename t1
join tablename t2 on t1.id = t2.id
where t1.Type = 'Name'
  and t2.Type = 'Text'

Answer 3

I would use exists :

select t.*
from t
where t.type = 'Name' and
      exists (select 1
              from t t2
              where t2.id = t.id and t2.type = 'Text'
             );

I would use join if I wanted to use any values from the "text" row. However, if I only want the "name" row, then I think exists is a more direct translation of the logic.