查找列表中哪些值小于/大于数字

Question

I've seen topics similar to this, but after trying out their methods it still didn't fix the part from if till the end. From what I read on other topics, the values are mismatched, yet I've been trying to fix it and trying out other methods with no success. Thank you for your help in advance. Here's my code:

numbers = []

def calc():

    d=0
    m=0
    single_number=int(input("Enter a number: "))
    number = input("Enter a list of numbers: ")
    numbers = [int(i) for i in number.split()]
    summed =sum(numbers, 0)/len(numbers)
    print("Average: ", summed)
    minimum=min(numbers)
    maximum=max(numbers)
    print("Minimum", minimum)
    print("Maximum", maximum)
    if numbers > single_number:
        d=d+1
    else:
        m=m+1
    print("Amount of numbers in the list that are smaller than the 1st entered number:", m)
    print("Amount of numbers in the list that are bigger than the 1st number:", d)
print(calc())

Answer 1

all you are missing is a loop:

for number in numbers: 
    if numbers > single_number:
        d=d+1
    else: # elif numbers < single_number: # what if numbers == single_number?
        m=m+1

there are improvements you could make though. d = d+1 is correct; i prefer d += 1 though.

then (if you don't mind looping over your list twice):

d = sum(1 for number in numbers if number > single_number)
m = sum(1 for number in numbers if number < single_number)

would give you d and m in a compact way.

Answer 2

if numbers > single_number is doing something like:

if [1, 2, 3, 4, 5, 6, 7] > 4

That doesn't make any sense. Do you want a for loop?

for number in numbers:
    if number > single_number:
        d += 1
    elif number < single_number:
        m += 1
    # else doesn't make sense here, since 4 is neither larger _nor_ smaller than 4.

Answer 3

You could use a list comprehension to filter and then get the length of the resulting list:

d = len([n for n in numbers if n > single_number])
m = len(numbers) - d