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Hibernate:插入多对一:错误列不能为空

[英]HIbernate: insert many to one: error Column cannot be null

Ho everyone, i have a problem when insert entity many to one.大家好,我在多对一插入实体时遇到问题。 problem: I wana insert a new record: staffId, type, reason.问题:我想插入一条新记录:staffId、类型、原因。 But table Records and employee have relationship many to one, so i dont know how to insert in this table with prop of class DTO is staffId or Employee employee, and how can i insert that.但是表记录和员工有多对一的关系,所以我不知道如何在这个表中插入类 DTO 的道具是员工 ID 或员工员工,我该如何插入。 Tks so much!太棒了!

code below:代码如下:

employee entity雇员实体

@Entity
@Table(name = "STAFF")
public class Employee {
@Column(name = "DEPARTMENT_ID")
private Long departmentId;
@ManyToOne(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
@JoinColumn(insertable = false, updatable = false)
private Department department;

Records entity记录实体

@Entity
@Table(name = "Records", catalog = "Assignment")
public class Records implements java.io.Serializable {

/**
 * 
 */
private static final long serialVersionUID = 1L;
private Long id;
private Employee Employee;
private boolean type;
private String reason;
private Date date;
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "StaffId", nullable = false)
public Employee getEmployee() {
    return this.Employee;

RecordDTO \\记录DTO \\

In controller, i dont know which class to use, Form or DTO public class RecordDto {在控制器中,我不知道要使用哪个类,Form 或 DTO 公共类 RecordDto {

  /*=====================================================================================================
 *===== PRIVATE PROPERTIES                                                                        =====
 *=====================================================================================================*/

/**
 * trunglq_department.ID
 */
private Long id;

/**
 * trunglq_department.Employee
 */
private Employee Employee;

/**
 * trunglq_department.type
 */
private boolean type;

/**
 * trunglq_department.reason
 */
private String reason;

/**
 * trunglq_department.date
 */
private Date date;

RecordForm记录表

public class RecordForm {

/*=====================================================================================================
 *===== PRIVATE PROPERTIES                                                                        =====
 *=====================================================================================================*/

/**
 * trunglq_department.ID
 */
private Long id;

/**
 * trunglq_department.Employee
 */
private int staffId;

/**
 * trunglq_department.type
 */
private boolean type;

/**
 * trunglq_department.reason
 */
private String reason;

/**
 * trunglq_department.date
 */
private Date date;

repository存储库

@Override
public Long insert(Records record) {
    record.setDate(new Date());
    return (Long)super.insert(record);
}

service服务

@Override
public Long create(RecordForm recordForm) {
    recordForm.setStaffId(9);
    Records record = (Records) DataTransformUtil.transform(recordForm, Records.class);
    return (Long)recordRepository.insert(record);
}

Controller控制器

In controller, i dont know which class to use, Form or DTO在控制器中,我不知道要使用哪个类,Form 还是 DTO

 @PostMapping("/create")
public String index(Model model, @ModelAttribute("formRecord") RecordForm recordForm,HttpServletRequest request) {
    recordService.create(recordForm);
    return "/employee/index";
}

JSP JSP

jsp is modal, i get data in table when click on a row. jsp 是模态的,单击一行时我会在表中获取数据。 in this, data include: staffId, type, reason.其中,数据包括:staffId、类型、原因。 Error code is null StaffId.错误代码为空 StaffId。

form:form modelAttribute="formRecord" action="record/create"
                method="POST">
                <!-- Modal Header -->
                <div class="modal-header">
                    <h4 class="modal-title">
                        Ghi nhận nhân viên có ID:
                            <label class="idStaff"
                            style="font-size: 20px"></label>
                    </h4>
                    <button type="button" class="close" data-dismiss="modal">&times;</button>
                </div>

                <!-- Modal body -->

                <div class="modal-body">
                        <form:hidden path="staffId" class="idStaff"/>
                    <div class="custom-control custom-radio custom-control-inline">
                        <form:radiobutton path="type" class="custom-control-input"
                            id="customRadio" name="radioRecord" value="0" />
                        <label class="custom-control-label" for="customRadio">Achievement</label>
                    </div>
                    <div class="custom-control custom-radio custom-control-inline">
                        <form:radiobutton path="type" class="custom-control-input"
                            id="customRadio2" name="radioRecord" value="1" />
                        <label class="custom-control-label" for="customRadio2">Mistake</label>
                    </div>
                    <div class="form-group">
                        <label for="reason">Reason:</label>
                        <form:textarea class="form-control" rows="5" id="comment"
                            path="reason" />
                    </div>

                </div>

                <!-- Modal footer -->
                <div class="modal-footer">
                    <button type="submit" class="btn btn-success">Save</button>
                    <button type="button" class="btn btn-danger" data-dismiss="modal">Close</button>
                </div>
            </form:form>

Error code错误代码

java.sql.SQLIntegrityConstraintViolationException: Column 'StaffId' cannot be null

Your staff pojo is missing staffId(PK).您的员工 pojo 缺少员工 ID(PK)。 Also why do you have department id if you already have a Department variable?另外,如果您已经有一个部门变量,为什么还要有部门 ID?

Your table might have staff_id, department_id, staff_name etc, so for many to one, you just need to add the foreign key reference and in pojos, you have to specific the joincolumn to be department_id.你的表可能有staff_id、department_id、staff_name等,所以对于多对一,你只需要添加外键引用,在pojos中,你必须将joincolumn指定为department_id。 similar to the Record entity you have.类似于您拥有的 Record 实体。

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