[英]How to convert Csv to Json using Node.js?
var csvToJson = require('convert-csv-to-json');
var fileInputName = 'Bangalore_schools.csv';
var fileOutputName = 'output.json';
csvToJson.generateJsonFileFromCsv(fileInputName, fileOutputName);
Csv File Link: Csv File Csv文件链接: Csv文件
But the above code i have used i am unable to fully convert it to json. 但是我使用的上述代码无法将其完全转换为json。 Please help.
请帮忙。 Output is coming like this.. i want to separate each key and its value likewise we have in json.
输出是这样的..我想像我们在json中一样分离每个键及其值。
[
{
"district|block|cluster|schoolid|schoolname|category|gender|medium_of_inst|address|area|pincode|landmark|identification1|busroutes|identification2|latlong": "-----------+---------+----------------------------+----------+-------------------------------------------+---------------+--------+----------------+---------------------------------------------------------------------------------------------------------------+-----------------------------------------+------------------+-----------------------------------------------------------------------------------------------+----------------------------------------------------------------------------------------------------+-------------------------------------------+-----------------------------------------------------------------------------------------------------+------------------------------------------"
},
{
"district|block|cluster|schoolid|schoolname|category|gender|medium_of_inst|address|area|pincode|landmark|identification1|busroutes|identification2|latlong": " bangalore|south-1|vajara halli|32868|GKHPS ALAHALLI|Upper Primary|co-ed|kannada|avalahalli south range- 1|bangalore|560062|masjid||||POINT(77.5766623020172 12.8893003120716)"
},
The default delimiter convert-csv-to-json
uses is a semicolon ( ;
). 默认的分隔符
convert-csv-to-json
使用的是分号( ;
)。 If you want to use a different delimiter, like |
如果要使用其他定界符,例如
|
the file you shared uses, you need to define it explicitly. 共享使用的文件,您需要明确定义它。 Eg:
例如:
csvToJson.fieldDelimiter('|').generateJsonFileFromCsv(fileInputName, fileOutputName);
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