[英]String of only even numbers and only odd numbers
I know there are already questions asking something similar to my question, but despite reading those, they don't quite do what I want. 我知道已经有一些问题在问与我的问题类似的东西,但是尽管阅读了这些内容,但它们并没有完全满足我的要求。 I am creating a code that takes a users input of a number between 0-100 (inclusive). 我正在创建一个代码,接受用户输入的0-100(含)之间的数字。 Whatever the number, it will print all the numbers leading up to that number and that number 无论数字是多少,它将打印出导致该数字和该数字产生的所有数字
EX: user input = 25 output = 012345678910111213141516171819202122232425 例如:用户输入= 25输出= 012345678910111213141516171819202122232425
I have that part working. 我有那部分工作。 Now I am supposed to use that string and create two new strings, one for only the odd and the other one for the even numbers. 现在,我应该使用该字符串并创建两个新字符串,一个仅用于奇数,另一个用于偶数。
EX: user input = 25 output: odd numbers: 135791113151719212325 & even numbers = 024681012141618202224 例如:用户输入= 25输出:奇数:135791113151719212325和偶数= 024681012141618202224
Here is my code so far: 到目前为止,这是我的代码:
import java.util.Scanner;
public class OddAndEven{
public String quantityToString() {
Scanner number = new Scanner(System.in);
int n = number.nextInt();
String allNums = "";
if ((n >= 0) && (n <= 100)) {
for (int i = 0;i <= n; ++i)
allNums = allNums + i;
return allNums;
}
else {
return "";
}
}
public void oddAndEvenNumbers(int num) {//Start of second method
String allNums = ""; //String that quantityToString returns
String odd = "";
String even = "";
if ((num >= 0) && (num < 10)) { //Looks at only single digit numbers
for (int i = 0; i <= allNums.length(); i++) {
if (Integer.parseInt(allNums.charAt(i))%2 == 0) { //trying to get the allNums string to be broken into individual numbers to evaluate
even = even + allNums.charAt(i); //adding the even numbers of the string
}
else {
odd = odd + allNums.charAt(i);
}
}
}
else { //supposed to handle numbers with double digits
for (int i = 10; i <= allNums.length(); i = i + 2) {
if (Integer.parseInt(allNums.charAt(i))%2 == 0) {
even = even + allNums.charAt(i);
}
else {
odd = odd + allNums.charAt(i);
}
}
}
System.out.println("Odd Numbers: " + odd);
System.out.println("Even Numbers: " + even);
}
public static void main(String[] args) {
System.out.println(new OddAndEven().quantityToString());
//System.out.println(new OddAndEven().oddAndEvenNumbers(allNums));
//Testing
OddAndEven obj = new OddAndEven();
System.out.println("Testing n = 5");
obj.oddAndEvenNumbers(5);
System.out.println("Testing n = 99");
obj.oddAndEvenNumbers(99);
I know my problem is at the part when its supposed to take the string apart and evaluate the individual numbers, but I don't know what to do. 我知道我的问题在于应该将字符串拆开并评估各个数字,但是我不知道该怎么办。 (I've also tried substring() & trim()) Also I have not learned how to use arrays yet, so that is why I did not try to use an array. (我也尝试过substring()&trim())而且我还没有学会如何使用数组,因此这就是为什么我没有尝试使用数组的原因。
I think you can make it that way: 我认为您可以这样:
int x = 20;
StringBuilder evenNumberStringBuilder = new StringBuilder();
StringBuilder oddNumberStringBuilder = new StringBuilder();
for(int i =0 ; i<x+1; i++){
if(i % 2 == 0)evenNumberStringBuilder.append(i);
else oddNumberStringBuilder.append(i);
}
System.out.println(evenNumberStringBuilder);
System.out.println(oddNumberStringBuilder);
Output: 输出:
02468101214161820
135791113151719
you are already taking the input as integer, so don't work with strings. 您已经将输入作为整数,所以不要使用字符串。 I recommend that to use this loop; 我建议使用此循环。
Scanner number = new Scanner(System.in);
System.out.print("Even Numbers: ");
for (int i = 0; i <= number; i=i+2) {
System.out.print(i);
}
System.out.println("");
System.out.print("Odd Numbers: ");
for (int i = 1; i <= number; i=i+2) {
System.out.print(i);
}
You can simply evaluate numbers while storing them in an allnumbers string, here's a functioning code: 您可以在将数字存储在allnumbers字符串中的同时简单地求值,这是一个起作用的代码:
int x = 23; //user input
String s=""; //contains all numbers from 0 to userinput
String odd =""; //contains all odd numbers from 0 to userinput
String even = ""; //contains all even numbers from 0 to userinput
for(int i = 0 ; i< x+1 ; i++){
s += i;
if(i%2==0) //if i is an even number
even += i;
else //if i is an odd number
odd += i;
}
System.out.println(s); //displaying all numbers from 0 to user input
System.out.println(odd); //displaying odd numbers from 0 to user input
System.out.println(even); //displaying even numbers from 0 to user input
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