[英]Python convert list to string in the dataframe
I have bunch of list and string like texts in the cell value of the pandas data frame.我在熊猫数据框的单元格值中有一堆列表和字符串,如文本。 I am trying to convert list to string, I am able to convert list to string, but its splitting the string as well.
我正在尝试将列表转换为字符串,我可以将列表转换为字符串,但它也会拆分字符串。 How do I only apply this logic if the cell contains list [] in the particular column?
如果单元格在特定列中包含列表 [],我如何仅应用此逻辑?
raw_data = {'Name': [['\'John Smith\''], ['\'Jane Doe\'']],
'id': [['\'A1005\'','\'A1006\''], 'A200,A400,A500']}
dfRaw = pd.DataFrame(raw_data, columns = ['Name','id'])
dfRaw['Name'] = dfRaw['Name'].astype(str)
Data数据
Name id
0 ["'John Smith'"] ['A1005', 'A1006']
1 ["'Jane Doe'"] A200,A400,A500
Need output like this:需要这样的输出:
Name id
0 ["'John Smith'"] 'A1005','A1006'
1 ["'Jane Doe'"] A200,A400,A500
But the code below is splitting string cell values too.但下面的代码也在拆分字符串单元格值。
dfRaw['id'] = dfRaw['id'].apply(lambda x: ','.join([str(i) for i in x]))
Name id
0 ["'John Smith'"] 'A1005','A1006'
1 ["'Jane Doe'"] A,2,0,0,,,A,4,0,0,,,A,5,0,0
You could use a list comprehension to generate a new list with the rows in id
joining those entries that are lists using string.join
.您可以使用列表
string.join
生成一个新列表,其中id
的行使用string.join
连接那些列表条目。 You can check if an entry is a list
using isinstance
:您可以使用
isinstance
来检查条目是否为list
:
df['id'] = [','.join(i) if isinstance(i, list) else i for i in df['id']]
Output
输出
Name id
0 ['John Smith'] A1005,A1006
1 ['Jane Doe'] A200,A400,A500
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