如何打破 Java 中的嵌套循环？

Question

I've got a nested loop construct like this:

for (Type type : types) {
    for (Type t : types2) {
         if (some condition) {
             // Do something and break...
             break; // Breaks out of the inner loop
         }
    }
}

Now how can I break out of both loops? I've looked at similar questions, but none concerns Java specifically. I couldn't apply these solutions because most used gotos.

I don't want to put the inner loop in a different method.

I don't want to return the loops. When breaking I'm finished with the execution of the loop block.

Answer 1

Like other answerers, I'd definitely prefer to put the loops in a different method, at which point you can just return to stop iterating completely. This answer just shows how the requirements in the question can be met.

You can use break with a label for the outer loop. For example:

public class Test {
    public static void main(String[] args) {
        outerloop:
        for (int i=0; i < 5; i++) {
            for (int j=0; j < 5; j++) {
                if (i * j > 6) {
                    System.out.println("Breaking");
                    break outerloop;
                }
                System.out.println(i + " " + j);
            }
        }
        System.out.println("Done");
    }
}

This prints:

0 0
0 1
0 2
0 3
0 4
1 0
1 1
1 2
1 3
1 4
2 0
2 1
2 2
2 3
Breaking
Done

Answer 2

Technically the correct answer is to label the outer loop. In practice if you want to exit at any point inside an inner loop then you would be better off externalizing the code into a method (a static method if needs be) and then call it.

That would pay off for readability.

The code would become something like that:

private static String search(...) 
{
    for (Type type : types) {
        for (Type t : types2) {
            if (some condition) {
                // Do something and break...
                return search;
            }
        }
    }
    return null; 
}

Matching the example for the accepted answer:

 public class Test {
    public static void main(String[] args) {
        loop();
        System.out.println("Done");
    }

    public static void loop() {
        for (int i = 0; i < 5; i++) {
            for (int j = 0; j < 5; j++) {
                if (i * j > 6) {
                    System.out.println("Breaking");
                    return;
                }
                System.out.println(i + " " + j);
            }
        }
    }
}

Answer 3

You can use a named block around the loops:

search: {
    for (Type type : types) {
        for (Type t : types2) {
            if (some condition) {
                // Do something and break...
                break search;
            }
        }
    }
}

Answer 4

I never use labels. It seems like a bad practice to get into. Here's what I would do:

boolean finished = false;
for (int i = 0; i < 5 && !finished; i++) {
    for (int j = 0; j < 5; j++) {
        if (i * j > 6) {
            finished = true;
            break;
        }
    }
}

Answer 5

You can use labels:

label1: 
for (int i = 0;;) {
    for (int g = 0;;) {
      break label1;
    }
}

Answer 6

Use a function:

public void doSomething(List<Type> types, List<Type> types2){
  for(Type t1 : types){
    for (Type t : types2) {
      if (some condition) {
         // Do something and return...
         return;
      }
    }
  }
}

Answer 7

You can use a temporary variable:

boolean outerBreak = false;
for (Type type : types) {
   if(outerBreak) break;
    for (Type t : types2) {
         if (some condition) {
             // Do something and break...
             outerBreak = true;
             break; // Breaks out of the inner loop
         }
    }
}

Depending on your function, you can also exit/return from the inner loop:

for (Type type : types) {
    for (Type t : types2) {
         if (some condition) {
             // Do something and break...
             return;
         }
    }
}

Answer 8

If you don't like break s and goto s, you can use a "traditional" for loop instead the for-in, with an extra abort condition:

int a, b;
bool abort = false;
for (a = 0; a < 10 && !abort; a++) {
    for (b = 0; b < 10 && !abort; b++) {
        if (condition) {
            doSomeThing();
            abort = true;
        }
    }
}

Answer 9

I needed to do a similar thing, but I chose not to use the enhanced for loop to do it.

int s = type.size();
for (int i = 0; i < s; i++) {
    for (int j = 0; j < t.size(); j++) {
        if (condition) {
            // do stuff after which you want 
            // to completely break out of both loops
            s = 0; // enables the _main_ loop to terminate
            break;
        }
    }
}

Answer 10

I prefer to add an explicit "exit" to the loop tests. It makes it clear to any casual reader that the loop may terminate early.

boolean earlyExit = false;
for(int i = 0 ; i < 10 && !earlyExit; i++) {
     for(int j = 0 ; i < 10 && !earlyExit; j++) { earlyExit = true; }
}

Answer 11

Java 8 Stream solution:

List<Type> types1 = ...
List<Type> types2 = ...

types1.stream()
      .flatMap(type1 -> types2.stream().map(type2 -> new Type[]{type1, type2}))
      .filter(types -> /**some condition**/)
      .findFirst()
      .ifPresent(types -> /**do something**/);

Answer 12

Usually in such cases, it is coming in scope of more meaningful logic, let's say some searching or manipulating over some of the iterated 'for'-objects in question, so I usually use the functional approach:

public Object searching(Object[] types) { // Or manipulating
    List<Object> typesReferences = new ArrayList<Object>();
    List<Object> typesReferences2 = new ArrayList<Object>();

    for (Object type : typesReferences) {
        Object o = getByCriterion(typesReferences2, type);
        if(o != null) return o;
    }
    return null;
}

private Object getByCriterion(List<Object> typesReferences2, Object criterion) {
    for (Object typeReference : typesReferences2) {
        if(typeReference.equals(criterion)) {
             // here comes other complex or specific logic || typeReference.equals(new Object())
             return typeReference;
        }
    }
    return null;
}

Major cons:

• roughly twice more lines
• more consumption of computing cycles, meaning it is slower from algorithmic point-of-view
• more typing work

The pros:

• the higher ratio to separation of concerns because of functional granularity
• the higher ratio of re-usability and control of searching/manipulating logic without
• the methods are not long, thus they are more compact and easier to comprehend
• higher ratio of readability

So it is just handling the case via a different approach.

Basically a question to the author of this question: what do you consider of this approach?

Answer 13

Labeled break concept is used to break out nested loops in java, by using labeled break you can break nesting of loops at any position. Example 1:

loop1:
 for(int i= 0; i<6; i++){
    for(int j=0; j<5; j++){
          if(i==3)
            break loop1;
        }
    }

suppose there are 3 loops and you want to terminate the loop3: Example 2:

loop3: 
for(int i= 0; i<6; i++){
loop2:
  for(int k= 0; k<6; k++){
loop1:
    for(int j=0; j<5; j++){
          if(i==3)
            break loop3;
        }
    }
}

Answer 14

You can break from all loops without using any label: and flags.

It's just tricky solution.

Here condition1 is the condition which is used to break from loop K and J. And condition2 is the condition which is used to break from loop K , J and I.

For example:

public class BreakTesting {
    public static void main(String[] args) {
        for (int i = 0; i < 9; i++) {
            for (int j = 0; j < 9; j++) {
                for (int k = 0; k < 9; k++) {
                    if (condition1) {
                        System.out.println("Breaking from Loop K and J");
                        k = 9;
                        j = 9;
                    }
                    if (condition2) {
                        System.out.println("Breaking from Loop K, J and I");
                        k = 9;
                        j = 9;
                        i = 9;
                    }
                }
            }
        }
        System.out.println("End of I , J , K");
    }
}

Answer 15

Use Labels.

INNER:for(int j = 0; j < numbers.length; j++) {
    System.out.println("Even number: " + i + ", break  from INNER label");
    break INNER;
}

Refer to this article

Answer 16

Best and Easy Method..

outerloop:
for(int i=0; i<10; i++){
    // here we can break Outer loop by 
    break outerloop;

    innerloop:
    for(int i=0; i<10; i++){
        // here we can break innerloop by 
        break innerloop;
     }
}

Answer 17

Demo

public static void main(String[] args) {
    outer:
    while (true) {
        while (true) {
            break outer;
        }
    }
}

Answer 18

boolean broken = false; // declared outside of the loop for efficiency
for (Type type : types) {
    for (Type t : types2) {
        if (some condition) {
            broken = true;
            break;
        }
    }

    if (broken) {
        break;
    }
}

Answer 19

Another one solution, mentioned without example (it actually works in prod code).

try {
    for (Type type : types) {
        for (Type t : types2) {
            if (some condition #1) {
                // Do something and break the loop.
                throw new BreakLoopException();
            }
        }
    }
}
catch (BreakLoopException e) {
    // Do something on look breaking.
}

Of course BreakLoopException should be internal, private and accelerated with no-stack-trace:

private static class BreakLoopException extends Exception {
    @Override
    public StackTraceElement[] getStackTrace() {
        return new StackTraceElement[0];
    }
}

Answer 20

Rather unusual approach but in terms of code length ( not performance ) this is the easiest thing you could do:

for(int i = 0; i++; i < j) {
    if(wanna exit) {
        i = i + j; // if more nested, also add the 
                   // maximum value for the other loops
    }
}

Answer 21

If it is inside some function why don't you just return it:

for (Type type : types) {
    for (Type t : types2) {
         if (some condition) {
            return value;
         }
    }
}

Answer 22

Demo for break , continue , and label :

Java keywords break and continue have a default value. It's the "nearest loop", and today, after a few years of using Java, I just got it!

It's seem used rare, but useful.

import org.junit.Test;

/**
 * Created by cui on 17-5-4.
 */

public class BranchLabel {
    @Test
    public void test() {
        System.out.println("testBreak");
        testBreak();

        System.out.println("testBreakLabel");
        testBreakLabel();

        System.out.println("testContinue");
        testContinue();
        System.out.println("testContinueLabel");
        testContinueLabel();
    }

    /**
     testBreak
     a=0,b=0
     a=0,b=1
     a=1,b=0
     a=1,b=1
     a=2,b=0
     a=2,b=1
     a=3,b=0
     a=3,b=1
     a=4,b=0
     a=4,b=1
     */
    public void testBreak() {
        for (int a = 0; a < 5; a++) {
            for (int b = 0; b < 5; b++) {
                if (b == 2) {
                    break;
                }
                System.out.println("a=" + a + ",b=" + b);
            }
        }
    }

    /**
     testContinue
     a=0,b=0
     a=0,b=1
     a=0,b=3
     a=0,b=4
     a=1,b=0
     a=1,b=1
     a=1,b=3
     a=1,b=4
     a=2,b=0
     a=2,b=1
     a=2,b=3
     a=2,b=4
     a=3,b=0
     a=3,b=1
     a=3,b=3
     a=3,b=4
     a=4,b=0
     a=4,b=1
     a=4,b=3
     a=4,b=4
     */
    public void testContinue() {
        for (int a = 0; a < 5; a++) {
            for (int b = 0; b < 5; b++) {
                if (b == 2) {
                    continue;
                }
                System.out.println("a=" + a + ",b=" + b);
            }
        }
    }

    /**
     testBreakLabel
     a=0,b=0,c=0
     a=0,b=0,c=1
     * */
    public void testBreakLabel() {
        anyName:
        for (int a = 0; a < 5; a++) {
            for (int b = 0; b < 5; b++) {
                for (int c = 0; c < 5; c++) {
                    if (c == 2) {
                        break anyName;
                    }
                    System.out.println("a=" + a + ",b=" + b + ",c=" + c);
                }
            }
        }
    }

    /**
     testContinueLabel
     a=0,b=0,c=0
     a=0,b=0,c=1
     a=1,b=0,c=0
     a=1,b=0,c=1
     a=2,b=0,c=0
     a=2,b=0,c=1
     a=3,b=0,c=0
     a=3,b=0,c=1
     a=4,b=0,c=0
     a=4,b=0,c=1
     */
    public void testContinueLabel() {
        anyName:
        for (int a = 0; a < 5; a++) {
            for (int b = 0; b < 5; b++) {
                for (int c = 0; c < 5; c++) {
                    if (c == 2) {
                        continue anyName;
                    }
                    System.out.println("a=" + a + ",b=" + b + ",c=" + c);
                }
            }
        }
    }
}

Answer 23

for (int j = 0; j < 5; j++) //inner loop should be replaced with for (int j = 0; j < 5 && !exitloops; j++) .

Here, in this case complete nested loops should be exit if condition is True . But if we use exitloops only to the upper loop

 for (int i = 0; i < 5 && !exitloops; i++) //upper loop

Then inner loop will continues, because there is no extra flag that notify this inner loop to exit.

Example : if i = 3 and j=2 then condition is false . But in next iteration of inner loop j=3 then condition (i*j) become 9 which is true but inner loop will be continue till j become 5 .

So, it must use exitloops to the inner loops too.

boolean exitloops = false;
for (int i = 0; i < 5 && !exitloops; i++) { //here should exitloops as a Conditional Statement to get out from the loops if exitloops become true. 
    for (int j = 0; j < 5 && !exitloops; j++) { //here should also use exitloops as a Conditional Statement. 
        if (i * j > 6) {
            exitloops = true;
            System.out.println("Inner loop still Continues For i * j is => "+i*j);
            break;
        }
        System.out.println(i*j);
    }
}

Answer 24

Using 'break' keyword alone is not the appropriate way when you need to exit from more than one loops. You can exit from immediate loop No matter with how many loops your statement is surrounded with. You can use 'break' with a label! Here I've used the label "abc" You can write your code as following, within any function in Java

This code shows how to exit from the most outer loop

 abc: 
    for (int i = 0; i < 10; i++) { 
        for (int j = 0; j < 10; j++) { 
           for (int k = 0; k < 10; k++) { 
              if (k == 1){
                 break abc;
              } 
        } 
    } 
}

Also you can use break statement to exit from any loop in a nested loop.

    for (int i = 0; i < 10; i++) { 
       abc:for (int j = 0; j < 10; j++) { 
           for (int k = 0; k < 10; k++) { 
              if (k == 1){
                 break abc;
              } 
        } 
    } 
}

The following code shows an example of exiting from the innermost loop. In other works,after executing the following code, you are at the outside of the loop of 'k' variables and still inside the loop of 'j' and 'i' variables.

    for (int i = 0; i < 10; i++) { 
        for (int j = 0; j < 10; j++) { 
           for (int k = 0; k < 10; k++) { 
              if (k == 1){
                 break;
              } 
        } 
    } 
}

Answer 25

Like @1800 INFORMATION suggestion, use the condition that breaks the inner loop as a condition on the outer loop:

boolean hasAccess = false;
for (int i = 0; i < x && hasAccess == false; i++){
    for (int j = 0; j < y; j++){
        if (condition == true){
            hasAccess = true;
            break;
        }
    }
}

Answer 26

If it's a new implementation, you can try rewriting the logic as if-else_if-else statements.

while(keep_going) {

    if(keep_going && condition_one_holds) {
        // Code
    }
    if(keep_going && condition_two_holds) {
        // Code
    }
    if(keep_going && condition_three_holds) {
        // Code
    }
    if(keep_going && something_goes_really_bad) {
        keep_going=false;
    }
    if(keep_going && condition_four_holds) {
        // Code
    }
    if(keep_going && condition_five_holds) {
        // Code
    }
}

Otherwise you can try setting a flag when that special condition has occured and check for that flag in each of your loop-conditions.

something_bad_has_happened = false;
while(something is true && !something_bad_has_happened){
    // Code, things happen
    while(something else && !something_bad_has_happened){
        // Lots of code, things happens
        if(something happened){
            -> Then control should be returned ->
            something_bad_has_happened=true;
            continue;
        }
    }
    if(something_bad_has_happened) { // The things below will not be executed
        continue;
    }

    // Other things may happen here as well, but they will not be executed
    //  once control is returned from the inner cycle.
}

HERE! So, while a simple break will not work, it can be made to work using continue .

If you are simply porting the logic from one programming language to Java and just want to get the thing working you can try using labels .

Answer 27

Java does not have a goto feature like there is in C++. But still, goto is a reserved keyword in Java. They might implement it in the future. For your question, the answer is that there is something called label in Java to which you can apply a continue and break statement. Find the code below:

public static void main(String ...args) {
    outerLoop: for(int i=0;i<10;i++) {
    for(int j=10;j>0;j--) {
        System.out.println(i+" "+j);
        if(i==j) {
            System.out.println("Condition Fulfilled");
            break outerLoop;
        }
    }
    }
    System.out.println("Got out of the outer loop");
}

Answer 28

It's fairly easy to use label , You can break the outer loop from inner loop using the label, Consider the example below,

public class Breaking{
    public static void main(String[] args) {
        outerscope:
        for (int i=0; i < 5; i++) {
            for (int j=0; j < 5; j++) {
                if (condition) {
                    break outerscope;
                }
            }
        }
    }
}

Another approach is to use the breaking variable/flag to keep track of required break. consider the following example.

public class Breaking{ 
    public static void main(String[] args) {
        boolean isBreaking = false;
        for (int i=0; i < 5; i++) {
            for (int j=0; j < 5; j++) {
                if (condition) {
                    isBreaking = true;
                    break;
                }
            }
            if(isBreaking){
                break;
            }
        }
    }
}

However, I prefer using the first approach.

Answer 29

You just use label for breaking inner loops

public class Test {
public static void main(String[] args) {
    outerloop:
for (int i=0; i < 5; i++) {
  for (int j=0; j < 5; j++) {
    if (i * j > 6) {
      System.out.println("Breaking");
      break outerloop;
    }
    System.out.println(i + " " + j);
  }
}
System.out.println("Done");
}
}

Answer 30

I've got a nested loop construct like this:

for (Type type : types) {
    for (Type t : types2) {
         if (some condition) {
             // Do something and break...
             break; // Breaks out of the inner loop
         }
    }
}

Now how can I break out of both loops? I've looked at similar questions, but none concerns Java specifically. I couldn't apply these solutions because most used gotos.

I don't want to put the inner loop in a different method.

I don't want to rerun the loops. When breaking I'm finished with the execution of the loop block.

Answer 31

boolean condition = false;
for (Type type : types) {
    for (int i = 0; i < otherTypes.size && !condition; i ++) {
        condition = true; // If your condition is satisfied
    }
}

Use condition as a flag for when you are done processing. Then the inner loop only continues on while the condition has not been met. Either way, the outer loop will keep on chuggin'.

Answer 32

I've got a nested loop construct like this:

for (Type type : types) {
    for (Type t : types2) {
         if (some condition) {
             // Do something and break...
             break; // Breaks out of the inner loop
         }
    }
}

Now how can I break out of both loops? I've looked at similar questions, but none concerns Java specifically. I couldn't apply these solutions because most used gotos.

I don't want to put the inner loop in a different method.

I don't want to rerun the loops. When breaking I'm finished with the execution of the loop block.

Answer 33

You can do the following:

1. set a local variable to false

2. set that variable true in the first loop, when you want to break

3. then you can check in the outer loop, that whether the condition is set then break from the outer loop as well.

    boolean isBreakNeeded = false; for (int i = 0; i < some.length; i++) { for (int j = 0; j < some.lengthasWell; j++) { //want to set variable if (){ isBreakNeeded = true; break; } if (isBreakNeeded) { break; //will make you break from the outer loop as well } }

Answer 34

Below is an example where "break" statement pushes the cursor out of the for loop whenever the condition is met.

public class Practice3_FindDuplicateNumber {

    public static void main(String[] args) {
        Integer[] inp = { 2, 3, 4, 3, 3 };
        Integer[] aux_arr = new Integer[inp.length];
        boolean isduplicate = false;
        for (int i = 0; i < aux_arr.length; i++) {

            aux_arr[i] = -1;

        }
        outer: for (int i = 0; i < inp.length; i++) {
            if (aux_arr[inp[i]] == -200) {
                System.out.println("Duplicate Found at index: " + i + " Carrying value: " + inp[i]);
                isduplicate = true;
                break outer;
            } else {
                aux_arr[inp[i]] = -200;
            }
        }

        for (Integer integer : aux_arr) {
            System.out.println(integer);
        }

        if (isduplicate == false) {
            System.out.println("No Duplicates!!!!!");
        } else {
            System.out.println("Duplicates!!!!!");
        }
    }

}

Answer 35

Check if the inner loop is exited with an if statement, by checking the inner loop's variable. You could also create another variable such as a boolean to check if the inner loop is exited.

In this example it uses the inner loop's variable to check if it has been exited:

int i, j;
for(i = 0; i < 7; i++){

for(j = 0; j < 5; j++) {

     if (some condition) {
         // Do something and break...
         break; // Breaks out of the inner loop
     }
}
     if(j < 5){    // Checks if inner loop wasn't finished
     break;    // Breaks out of the outer loop   
     } 
}

Answer 36

I feel using labels makes the code seem very much like a goto statement. This is just a thought.

Instead, throw an exception at the inner for loop and encapsulate the two for loops with a try catch block.

Something like

try {
  // ...
  for(Object outerForLoop : objectsOuter) {
     // ...
     for (Object innerForLoop : objectsInner) {
        // ...
        if (isConditionTrue)
             throw new WrappedException("With some useful message. Probably some logging as well.");
     }
  }
  catch (WrappedException) {
        // Do something awesome or just don't do anything to swallow the exception.
  }

Just a thought. I prefer this code since it gives me better loggability (like that's a word) for me when this is being run in production or something.