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我不明白我的编译器如何在C ++中获得此输出

[英]I don't understand how my compiler got this output in C++

My C++ program is as follows: 我的C ++程序如下:

#include<iostream>
#include<conio.h>
using namespace std;

int a;
struct CARE{
    long L1;
    void init()
    {
        L1=100;
    }
    void intake()
    {
        a++;
        L1+=++a;
    }
    void takeout()
    {
        int k=5;
        cout<<a*k<<'#'<<L1-a;
    }
};
int main()
{
    CARE c[3];
    for(int i=0;i<3;i++)
       c[i].init();
    for(int j=0;j<3;j++)
       c[j].intake();
    for(int m=0;m<3;m++)
       c[m].takeout();
    return 0;
    getch();
}

And the output comes out to be: 输出结果是:

30#9630#9830#100 30#9630#9830#100

According to me 'a' would be a junk variable and every output would be different from the other but that is not the case here. 根据我的说法,“ a”将是一个垃圾变量,每个输出都将与另一个不同,但是这里不是这种情况。 Can someone explain why? 有人可以解释为什么吗?

a is at global scope, so it's initialised to 0 . a在全局范围内,因此初始化为0

(Indeed if it was declared in a function then it would not be initialised and your program behaviour would be undefined.) (实际上,如果在函数中声明了它,则不会对其进行初始化,并且您的程序行为将是不确定的。)

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