表单基于值提交到URL

Question

This may sound weird but i trying to make a form that submit to different page according to the value of database

Database

| value | etc.Info 
    1
  -----

Code

<form action="?I donno put what to determind them to go?" method="POST">
<input type="hidden" name="id" value="<?php echo $row['id']; ?>" />
<input type="submit" class="btn btn-primary btn-sm" value="Edit"/>
</form>

And my wish is to click the button and go to another page with name upload.php when the value is 1 on database and go to detail.php when the value is 0, any advice will be good and i thank you in advance who all wish to help

Answer 1

<form action="anotherpage.php" method="POST">

In anotherpage.php

$yourhiddenvalue= $_POST['id'];
if($yourhiddenvalue ==0){
//redirect to detail.php
}
if($yourhiddenvalue ==1){
//redirect to upload.php
}

Answer 2

If you know the ID when the page loads you can do

if($_POST['id'] == 0) {
    $location = "detail.php";
} else {
    $location = "upload.php";
}

You can also do this is a switch statement if there are more than two options.

then your form would be

<form action="<?php echo $location; ?>" method="POST">