[英]Select three records in a single query of a cross table that contains records of two tables - MYSQL
I have a main table called "product"
that is linked with three tables: 我有一个称为
"product"
的主表,该主表与三个表链接:
"product_type",
"feature",
"type_feature"
and a cross table called "product_feature"
that contains several features of the same product. 还有一个称为
"product_feature"
的交叉表,其中包含同一产品的多个功能。
Example one record: 示例一记录:
I have something similar like this: 我有类似的东西:
product_type 产品类别
id_product_type name
1 Phone
feature 特征
id_feature name
1 Memory
2 Color
3 Memory Ram
feature_type FEATURE_TYPE
id_feature_type id_feature value
1 1 16GB
2 1 32GB
3 2 Blue
4 2 Black
5 3 2GB
6 3 3GB
product 产品
id_product id_product_type price quantity model
1 1 100$ 5 Moto-G7
Cross table "product_feature" (linked to "product", "feature" and "feature_type"): 交叉表“ product_feature”(链接到“ product”,“ feature”和“ feature_type”):
id_feature id_product id_feature_type
1 1 1
2 1 3
3 1 6
I want query show this: 我想查询显示此:
id_product type_name price quantity model feature_name value
1 Phone 100$ 5 Moto-G7 Memory 16GB
feature_name2 value2 feature_name3 value3
Color Blue Memory Ram 3GB
I tried this, but only I have only one feature_name and value, and I need three: 我试过了,但是只有我只有一个feature_name和value,我需要三个:
SELECT p.id_product, pt.name, model, price, quantity, f.name AS feature, ft.value
FROM product p
LEFT JOIN product_type pt ON pt.id_product_type = p.id_product_type
LEFT JOIN product_feature pf ON pf.id_product = p.id_product
LEFT JOIN feature f ON f.id_feature = pf.id_feature
LEFT JOIN feature_type ft ON ft.id_feature_type = pf.id_feature_type
GROUP BY p.id_product;
Try this query, It will give you the results: 试试这个查询,它将为您提供结果:
SELECT product.*, product_type.name as TypeName, (SELECT CONCAT( GROUP_CONCAT(feature_type.value), "|", GROUP_CONCAT(feature.name) ) FROM `product_feature` INNER JOIN feature_type on product_feature.id_feature_type = feature_type.id_feature_type INNER JOIN feature on feature_type.id_feature = feature.id_feature WHERE product_feature.id_product=1 GROUP BY product_feature.id_product) as options FROM `product` LEFT JOIN product_type on product.id_product_type = product_type.id_product_type
You will get options for your product and you have to explode() those options by "|" 您将获得产品的选项,并且必须通过“ |”将这些选项炸开()。 and you can count how many options you have by using $count= count(explode("|", $options))
并且您可以通过使用$ count = count(explode(“ |”,$ options))来计数您拥有多少个选项
By this way you can get all options . 通过这种方式,您可以获得所有选择。
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