获取正则表达式以匹配同一模式的多个实例

Question

So I have this regex - regex101 :

\[shortcode ([^ ]*)(?:[ ]?([^ ]*)="([^"]*)")*\]

Trying to match on this string

[shortcode contact param1="test 2" param2="test1"]

Right now, the regex matches this:

[contact, param2, test1]

I would like it to match this:

[contact, param1, test 2, param2, test1]

How can I get regex to match the first instance of the parameters pattern, rather than just the last?

Answer 1

Try using the below regex.

regex101

Below is your use case,

var testString = '[shortcode contact param1="test 2" param2="test1"]';

var regex = /[\\w\\s]+(?=[\\="]|\\")/gm;

var found = paragraph.match(regex);

If you log found you will see the result as

["shortcode contact param1", "test 2", " param2", "test1"]

The regex will match all the alphanumeric character including the underscore and blank spaces only if they are followed by =" or " .

I hope this helps.

Answer 2

You may use

'~(?:\G(?!^)\s+|\[shortcode\s+(\S+)\s+)([^\s=]+)="([^"]*)"~'

See the regex demo

Details

• (?:\\G(?!^)\\s+|\\[shortcode\\s+(\\S+)\\s+) - either the end of the previous match and 1+ whitespaces right after ( \\G(?!^)\\s+ ) or ( | )
  • \\[shortcode - literal string
  • \\s+ - 1+ whitespaces
  • (\\S+) - Group 1: one or more non-whitespace chars
  • \\s+ - 1+ whitespaces
• ([^\\s=]+) - Group 2: 1+ chars other than whitespace and =
• =" - a literal substring
• ([^"]*) - Group 3: any 0+ chars other than "
• " - a " char.

PHP demo

$re = '~(?:\G(?!^)\s+|\[shortcode\s+(\S+)\s+)([^\s=]+)="([^"]*)"~';
$str = '[shortcode contact param1="test 2" param2="test1"]';
$res = [];
if (preg_match_all($re, $str, $matches, PREG_SET_ORDER, 0)) {
    foreach ($matches as $m) {
        array_shift($m);
        $res = array_merge($res, array_filter($m));
    }
}
print_r($res);
// => Array( [0] => contact [1] => param1  [2] => test 2 [3] => param2  [4] => test1 )