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使用同一父级的表亲节点从父级中选择子元素

[英]Select a child element from a parent using a cousin node of the same parent

I'm using TestCafe Selectors to select elements. 我正在使用TestCafe选择器来选择元素。 This is a complex nested scenario of cousin child. 这是表亲孩子的复杂嵌套场景。

Here is the HTML to get an idea of what I mentioned above: 这是HTML,以了解我上面提到的内容:

HTML

In the picture, I have mentioned 1 and 2 which are the parent element (has same DOM) who has a grand grand child path and the same parent's grand grand child in the other tree is <span title='John' /span> . 在图片中,我提到了12 ,它们是父元素(具有相同的DOM),具有宏大的子path ,而另一个树中的同一父母的大祖儿是<span title='John' /span> I need the node of the path but need to link <span title='John' /span> because all the parents have the same DOM. 我需要path的节点,但需要链接<span title='John' /span>因为所有父节点都有相同的DOM。

I don't know how to resolve this situation using TestCafe. 我不知道如何使用TestCafe解决这种情况。 Do I have to use jQuery? 我必须使用jQuery吗? If yes, then how? 如果是,那怎么样? I tried a lot but couldn't figure out. 我试了很多但是想不出来。

TestCafe API is smart enough to handle your case: TestCafe API非常智能,可以处理您的情况:

const JohnSelector = Selector('div.person-identity')
  .find('span.person-name')
  .withExactText('John');

const pathSelector = JohnSelector
  .parent('div.projects-project-role')
  .prevSibling('div.projects-project-role')
  .find('button svg path')
  .nth(1);

console.log(`${await JohnSelector.innerText}`);
console.log(`${await pathSelector.getAttribute("d")}`);

In jQuery you can fetch all the elements with class projects-project-role , and then search each of those elements for a path tag and an element of the class person-name , and add their values to an array, like this: jQuery您可以使用类projects-project-role获取所有元素,然后在每个元素中搜索path标记和类person-name的元素,并将它们的值添加到数组中,如下所示:

var namePath = []; // initialize empty name/path array
$(".projects-project-role").each(function() {  // go through each element of class projects-project-role
    var path = $(this).find("path").attr("d"); // look for a path tag subelement and grab its d attribute
    var name = $(this).find(".person-name").text(); // look for an element of class person-name and grab its text
    namePath.push({path: path, name: name}); // add the gathered path and name to an array
});
console.log(namePath); // display the array

EDIT: Or in shorthand, and with map : 编辑:或者用速记,并用map

var namePath = $(".projects-project-role").get().map((p)=>({path: $(p).find('path').attr('d'), name: $(p).find('.person-name').text()}));
console.log(namePath); // display the array

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