如何使用Groovy替换json文件中的参数值

Question

Is there any simple way to replace the version from " 1.0.2 " to " 2.6.5 " in a json file " deploy.json " using groovy scripting , and the file content has been provided below.

{
  "versions": [
        {
            "version": "1.0.2",
            "conf": "replian"
        },
        {
            "version": "1.0.2",
            "conf": "hp"
        },
        {
            "version": "1.0.2",
            "conf": "shutoff"
        },
        {
            "version": "1.0.2",
            "conf": "spark"
        }
            ]
}

I tried the below, but getting an error;

import groovy.json.JsonBuilder
import groovy.json.JsonSlurper

def content = """
{
  "versions": [
        {
            "version": "1.0.2",
            "conf": "replian"
        },
        {
            "version": "1.0.2",
            "conf": "hp"
        },
        {
            "version": "1.0.2",
            "conf": "shutoff"
        },
        {
            "version": "1.0.2",
            "conf": "spark"
        }
            ]
}"""

def slurped = new JsonSlurper().parseText(content)
def builder = new JsonBuilder(slurped) 
builder.content.versions.find{it.version}.version = "2.6.5"
println(builder.toPrettyString())

ISSUE: Only first conf version is replaced eg { "version": "2.6.5", "conf": "replian" }, { "version": "1.0.2", "conf": "hp" }, { "version": "1.0.2", "conf": "shutoff" }, { "version": "1.0.2", "conf": "spark" }

Answer 1

Using jq :

$ jq '.versions[].version="2.6.5"' deploy.json
{
  "app": "Beach",
  "Process": "steam",
  "versions": [
    {
      "version": "2.6.5",
      "conf": "replian"
    }, ...

Or awk, if you must:

$ awk '
BEGIN {
    FPAT="([^:]*)|(\"[^\"]+\")"
    OFS=":"
}
$1~"\"version\"" {
    sub(/"[^"]*"/,"\"2.6.5\"",$2)
}1' deploy.json

Some output:

{
  "app": "Beach",
  "Process": "steam",
  "versions": [
        {
            "version": "2.6.5",
            "conf": "replian"
        }, ...

Answer 2

I like to suggest groovy to do this.

Edited : See the // Edited Line

import groovy.json.JsonBuilder
import groovy.json.JsonSlurper

def content = """
{
  "app": "Beach",
  "Process": "steam",
  "versions": [
        {
            "version": "1.0.2",
            "conf": "replian"
        },
        {
            "version": "1.0.2",
            "conf": "hp"
        },
        {
            "version": "1.0.2",
            "conf": "shutoff"
        },
        {
            "version": "1.0.2",
            "conf": "spark"
        }
            ]
}"""

def slurped = new JsonSlurper().parseText(content)
def builder = new JsonBuilder(slurped) 
builder.content.versions.find{it.version}.version = "2.6.5" // Edited Line
println(builder.toPrettyString())

// Updated Line
new File ("out.json").text = builder.toPrettyString()

Answer 3

如果您对sed感兴趣： sed 's/"version": "1\\.0\\.2"/"version": "2.6.5"/ deploy.json