Python，Selenium-无法找到ID为“ next”的网页元素（按钮）

Question

I started learning python with selenium to automate some of my tasks. I have a problem which I'm unable to solve.
I'm trying to create a script which would automatically click the 'next' button. I can't locate a webpage element (button) with ID 'next'. I tried every possible solution - by ID, by xpath etc.
It's possible that part of the webpage in which I'm trying to find the element is dynamically generated by jquery.
This is the error I get:

Unable to locate element: [id="next"]

Here is what I've done until this point (fragments):

from selenium import webdriver
from selenium.common.exceptions import WebDriverException
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
import time
from selenium.common.exceptions import TimeoutException
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By

browser = webdriver.Firefox(executable_path=r'C:\Users\technik 
informatyk\Desktop\python\geckodriver.exe')

browser.get('https://it-szkola.edu.pl/usr')
browser.maximize_window()
browser.implicitly_wait(3)

zgoda = browser.find_element_by_xpath('//*[@id="cookieLayerBoxButton"]')
zgoda.click()

browser.implicitly_wait(10) 
emailElem = browser.find_element_by_id('login-box-field-input')
emailElem.send_keys('mylogin')

passwordElem = browser.find_element_by_id('password')
passwordElem.send_keys('mypassword')
passwordElem.submit()
time.sleep(2)
aktualnosci = browser.find_element_by_id('hBLAkt').click()
grandtest = browser.find_element_by_xpath('//* [@id="New178"]/div[2]/div[1]/p[2]/a').click()
lista = browser.find_element_by_link_text('Lista testów').click()
test = WebDriverWait(browser, 10).until(EC.presence_of_element_located((By.XPATH,"/html/body/div[2]/div[1]/div[2]/table/tbody/tr[5]/td[5]/a"))).click()

#browser.refresh()
#time.sleep(2)
nastepne = browser.find_element_by_id("next")

#nastepne = WebDriverWait(browser, 10).until(EC.presence_of_element_located((By.LINK_TEXT, "Następne")))
#nastepne = browser.find_element_by_link_text('Następne').click()
nastepne.click()

Screenshots ,

,

,

,

,

Your help will be much appreciated.

Answer 1

Try xpath: browser.find_element_by_xpath('//button[@id="next"]')

Try getting all buttons:

btns = browser.find_elements_by_xpath('//button')
for btn in btns:
    txt = btn.text
    if txt == 'Następne':
         btn.click()