[英]How do I display Today and Yesterday using date?
I am fetching data from the database. 我正在从数据库中获取数据。 Now I have a date which is below
现在我有一个日期低于
`2019-03-10 04:50:26`
`2019-03-09 01:30:55`
`2019-03-08 16:22:45`
What I am doing is, If the date is today's date then " Today
" if the date is yesterday date then display " Yesterday
" else display actual date. 我正在做的是,如果日期是今天的日期,那么“
Today
”,如果日期是昨天的日期,则显示“ Yesterday
”,否则显示实际日期。
My expected output is 我的预期输出是
Today | Sunday
Yesterday | Saturday
8th March 2019 | Friday
I tried below code. 我尝试下面的代码。
$nofiDate=date('jS F Y', strtotime($result->created_added)); // getting `8th March 2019`
$day = date('l', strtotime($result->created_added)); // getting days name "Friday"
using the above code I am getting output is 8th March 2019 | Friday
使用上面的代码,我得到的输出是
8th March 2019 | Friday
8th March 2019 | Friday
but how do I display today and Yesterday using date? 但是如何显示今天和昨天的使用日期?
You need to do if else comparison, if date is equal today date then assign variable $day = 'Today' else if subtracted by one day must be Yesterday This code should work 您需要进行其他比较,如果日期等于今天的日期,则分配变量$ day ='Today',否则如果减去一天则必须是昨天
if($day==date('l')){
$day = 'Today';
}else if(date('l', now() - (24 * 60 * 60))){
$day = 'Yesterday';
}
Convert a time today and yesterday to date strings in the same format that you're using. 将今天和昨天的时间转换为与您使用的格式相同的日期字符串。 Then compare with them, and replace with the words you want.
然后与它们进行比较,并用所需的单词替换。
$today = date("jS F Y");
$yesterday = date("jS F Y", time() - 86400); // 86400 seconds in a day
Then you can compare $nofiDate
with those, and show the strings you want instead: 然后,您可以将
$nofiDate
与之比较,并显示所需的字符串:
if ($nofiDate == $today) {
$nofiDate = "Today";
} elseif ($nofiDate == $yesterday) {
$nofiDate = "Yesterday";
}
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