[英]How can I make an async Task return true or false?
I am calling a task like this in my method: 我在我的方法中调用了这样的任务:
if (Settings.mode.IsPractice() && App.practiceRunning != true)
{
// I want to call this method and check if it returned true or false
await IsPractice();
}
private async Task IsPractice()
{
// I want to return true or false from here
}
How can I return from the method based on the value of the IsPractice() returning a true or false? 如何基于IsPractice()的值返回true或false的方法从方法返回? Looks like the async method returns just a Task but I need to know if it ran and returned a true or a false.
看起来async方法仅返回一个Task,但我需要知道它是否已运行并返回true或false。
Use the generic Task type: 使用通用任务类型:
if (Settings.mode.IsPractice() && App.practiceRunning != true)
{
if (await IsPractice()) {
// Do something here
}
}
private async Task<bool> IsPractice()
{
return true;
}
private static async Task<bool> IsPractice()
{
return true;
}
and in async method receive like this 并在异步方法中收到这样
bool x = await IsPractice();
just add <bool>
只需添加
<bool>
private async Task<bool> IsPractice()
{
return true;
}
or just use async bool
或只使用
async bool
private async bool IsPractice()
{
return true;
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.