交叉检查两个表

Question

I have two table in my database, one contain attendance of employees while the other contains payroll of employees. inorder for an employee to get paid his name should exist on both table, my question is how to write the program that looks in the two table using id of an employee and list names that found ......am working with php and mysql

attendance table

id   name        
1    mark

2    jhon

payroll table

id     name      salary
1      mark      20000$
2      jhon      3999$

Answer 1

You can use join query to fetch data from those tables. If you do not know how to use it then take a look at the following link SQL Join tutorial

Answer 2

Maybe you can use an JOIN. In this case a INNER JOIN should do the trick. But there are also other kind of joins.

Select all records from Table A and Table B, where the join condition is met.

Select all records from Table A, along with records from Table B for which the join condition is met (if at all).

Select all records from Table B, along with records from Table A for which the join condition is met (if at all).

Select all records from Table A and Table B, regardless of whether the join condition is met or not.

In this case you can use the INNER JOIN like this

SELECT attendance.name, payroll.salary FROM attendance INNER JOIN payroll ON attendance.name = payroll.name

This will select the name and the salary if they exist.

Maybe you should change the key names to the ones in your database

For the record, got the images from http://www.sql-join.com/sql-join-types