将两个查询合并为一个查询Laravel

Question

I need to combine two queries into one so i can call it one time on my foreach inside a table in my blade view. I tried using merge() but it displays two separate queries. CountofPatents are all the patents that were submitted by a user and CountofApprovedPatents are the patents which has the status of "2". Here's how it looks now:

array 0 [person_id : 1
CountofApprovedPatents: 4
status: 2]

array 1 [person_id : 2
CountofApprovedPatents: 2
status: 2]

array 2 [person_id : 1
CountofPatents: 5]

array 3 [person_id : 2
CountofPatents: 4]

Here's how it's supposed to look like

array 0 [person_id : 1
CountofApprovedPatents: 4
CountofPatents: 5]

array 1 [person_id : 2
CountofApprovedPatents: 2
CountofPatents: 4]

Here's my code so far

AdminController

$start = $request->input('start');
$end = $request->input('end');
$approvedPatents = DB::table('patents')
->select('person_id', DB::raw('count(*) as CountofApprovedPatents'))
->where([
    ['status', '=', 2],
    ['date_approved', '>=', $start],
    ['date_approved', '<=', $end],
])
->groupBy('person_id')
->orderBy('status', 'desc')
->get();

$totalPatents = DB::table('patents')
->select('person_id', DB::raw('count(*) as CountofPatents'))
->where([
    ['date_approved', '>=', $start],
    ['date_approved', '<=', $end],
])
->groupBy('person_id')
->orderBy('status', 'desc')
->get();  

$patents = $approvedPatents->merge($totalPatents);
$results = $patents->all();  
return view('admin.patents.showPatents', compact('results', 
'start', 'end'));

Is it possible to combine these two queries?

$results = DB::table('patents')
    ->union($approvedPatents)
    ->union($totalPatents)
    ->get();

Answer 1

What I think you are looking for is Unions .

It'll allow you to specify a query and then join it with the final query.

Eg.

$first = DB::table('users')
            ->whereNull('first_name');

$users = DB::table('users')
            ->whereNull('last_name')
            ->union($first)
            ->get();

Try:

$approvedPatents = DB::table('patents')
->select('person_id', DB::raw('count(*) as CountofApprovedPatents, status'))
->where([
    ['status', '=', 2],
    ['date_approved', '>=', $start],
    ['date_approved', '<=', $end],
])
->groupBy('person_id')
->orderBy('status', 'desc')


$totalPatents = DB::table('patents')
->select('person_id', DB::raw('count(*) as CountofPatents'))
->where([
    ['date_approved', '>=', $start],
    ['date_approved', '<=', $end],
])
->groupBy('person_id')
->orderBy('status', 'desc')
->union($approvedPatents)
->get();  

Otherwise you could be looking for Joins - worth a look at the docs :)

Unions: https://laravel.com/docs/5.8/queries#unions

Joins: https://laravel.com/docs/5.8/queries#joins

Answer 2

You can use MySQL's IF condition in your raw selection of columns.

$results = DB::table('patents')
->select('person_id', 
          DB::raw('sum(IF(status = 2,1,0)) as CountofApprovedPatents'),
          DB::raw('count(*) as CountofPatents')
->where([
    ['date_approved', '>=', $start],
    ['date_approved', '<=', $end],
])
->groupBy('person_id')
->orderBy('status', 'desc')
->get();

The above IF condition in sum() adds 1 to the result if current row's status is 2 , else it adds 0 which effectively doesn't break the sum.