[英]Extract string with in parenthesis if matched (regex)
The string could be as follows.该字符串可能如下所示。
poptype in ('01')
and (a0='169'or a1='169'or a2='169'or a3='169'or a4='169'or a5='169'or a6='169'or a7='169'or a8='169'or a9='169')
and (sku in ('67798240','67724312','67724313','67460442','67629434'))
and (geo_code in ('D01365','D01353','D01354','D01356','D01364','D01357','D01555'))
The result should be as follows:结果应如下所示:
Output required:所需输出:
(a0='169'or a1='169'or a2='169'or a3='169'or a4='169'or a5='169'or a6='169'or a7='169'or a8='169'or a9='169')
If "a0" or "a9" exists in a string, I want to match whole wordings within first parent parenthesis.如果字符串中存在“a0”或“a9”,我想匹配第一个括号内的整个措辞。
This should do it:这应该这样做:
\(.*(?:a0|a9).*\)
Check out at: https://regex101.com/r/SWtZh4/1 Basically it matches everything within the brackets if a0 or a9 have been found in it.查看: https ://regex101.com/r/SWtZh4/1 如果在括号中找到 a0 或 a9,它基本上匹配括号内的所有内容。
If "a0" or "a9" exists in a string, I want to match whole wordings within first parent parenthesis.
如果字符串中存在“a0”或“a9”,我想匹配第一个括号内的整个措辞。
(\\([^\\(]+(a0|a9)[^\\)]+\\))
That should basically do what you want.这基本上应该做你想做的。
Looking for a opening brace, followed by any number of non-opening-brace characters, then a0 or a9, and then "mirrored" for the closing brace on the other end.寻找左大括号,后跟任意数量的非左大括号字符,然后是 a0 或 a9,然后“镜像”另一端的右大括号。
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