如何使用邮递员休息客户端将自定义dto作为休息api输入传递

Question

Here is my code ,I'm trying to pass the user details as a json input but I'm not able to receive the data in my rest api method. I"m getting all values as null,

this is my json request

{
    "userId" : "12345",
    "username" : "arun.ammasai",
    "createdBy" : "-2",
    "updatedBy" : "-2",
    "statusCd" : "New",
    "createdDate" : "2019-03-03",
    "updatedDate" : "2019-03-03"
}

====================================================================

@RequestMapping(value = "/registerUser", method = RequestMethod.POST, consumes = { "application/JSON", "application/XML" })
private String registerUser(User user) {
    System.out.println(user.toString());
    return "User Created";
}

====================================================================

here is the response in Postman Client

Unexpected 'U'

Answer 1

Update your method signature with @RequestBody annotation. It will automatically deserialize your json into java entity. Be carefull, names in json should be the same as parameters in User object and User object should have getters and setters. So your method should look like

    @RequestMapping(value = "/registerUser", method = RequestMethod.POST, consumes = { "application/JSON", "application/XML" })
        private String registerUser(@RequestBody User user) {
            System.out.println(user.toString()); //What is the reason of doing toString of java Object? 
            //better to do System.out.println(user.getUsername())
            return "User Created";
    }