[英]Embed luac-bytecode into C/C++ source-file
How do you include a lua-bytecode-string into a C/C++ file ? 您如何在C / C ++文件中包含lua-bytecode-string?
$ luac -o test -s test.lua
$ cat test
LuaS�
xV(w@@A@$@&�printTestj
Now if you could insert this byte-string into a C/C++-file, you could actually 现在,如果您可以将此字节字符串插入C / C ++文件,则实际上
luaL_loadfile(lua, bytestring.c_str());
which makes it unnecessary to load test.lua
at run-time. 这样就不必在运行时加载test.lua
。 You would not even have to interpret test.lua
at run-time, right? 您甚至test.lua
在运行时解释test.lua
,对吗?
Update: 更新:
The first two comments to this question were helpful for generating a bytestring so that you can include it in your C/C++ code. 该问题的前两个注释有助于生成字节字符串,以便您可以将其包括在C / C ++代码中。 From this answer I got this idea: 从这个答案我得到了这个主意:
xxd -i test > test.h
which creates this: 这创建了这个:
unsigned char test[] = {
0x1b, 0x4c, 0x75, 0x61, 0x53, 0x00, 0x19, 0x93, 0x0d, 0x0a, 0x1a, 0x0a,
0x04, 0x08, 0x04, 0x08, 0x08, 0x78, 0x56, 0x00, /* ... */, 0x00};
unsigned int test_len = 105;
This is great, but this will not work with luaL_loadstring , since 很好,但这不适用于luaL_loadstring ,因为
This function uses lua_load to load the chunk in the zero-terminated string s. 此函数使用lua_load将块加载到以零结尾的字符串s中。
Note: there are zeros as data in test
. 注意: test
数据为零 。
使用luaL_loadbuffer代替luaL_loadstring :
luaL_loadbuffer(L,test,test_len,"");
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