[英]I want to convert XML to Java by unmarshalling
This is my XML, and I want to unmarshall it. 这是我的XML,我想解组。
<?xml version="1.0" encoding="UTF-8"?>
<departments>
<deptname name="Research">
<employee>
<eid>r-001</eid>
<ename>Dinesh R</ename>
<age>35</age>
<deptcode>d1</deptcode>
<deptname>Research</deptname>
<salary>20000</salary>
</employee>
</deptname>
<deptname name="Sales">
<employee>
<eid>s-001</eid>
<ename>Kanmani S</ename>
<age>35</age>
<deptcode>d2</deptcode>
<deptname>Sales</deptname>
<salary>30000</salary>
</employee>
</deptname>
</departments>
Department.java 部门.java
public class Department
{
@XmlAttribute(name = "deptname")
private String name;
@XmlElement(name = "employee")
private List<Employee> employee = new ArrayList<>();//getter and setter//
}
This is my Departments.java 这是我的Departments.java
public class Departments {
List<Department> deptname;
public List<Department> getDeptname() {
return deptname;
}
public void setDeptname(List<Department> deptname) {
this.deptname = deptname;
}
}
This is my Unmarshalling.java 这是我的Unmarshalling.java
public class Unmarshalling {
public void testXML() {
try {
File file = new File(
"/home/scrunch/work/workspace/sts/default/EmployeeUnmarshall/src/main/java/OutputXml.xml");
JAXBContext jaxbContext = JAXBContext.newInstance(Departments.class);
Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
Departments departments = (Departments) jaxbUnmarshaller.unmarshal(file);
System.out.println(departments);
} catch (JAXBException e) {
e.printStackTrace();
}
}
}
I have tried unmarshalling but i didn't get the java object .I got xml format. 我曾尝试解组,但没有得到java对象。我得到了xml格式。 I am doing the Rest service. 我在做休息服务。 For that, I need to unmarshall the XML file, so then I could get the Java objects.Could you please update me sir. 为此,我需要解组XML文件,然后才能获取Java对象。先生,请给我更新一下。
I tried your code and ended up having this error: 我尝试了您的代码,并最终出现此错误:
Exception in thread "main" javax.xml.bind.UnmarshalException: unexpected element (uri:"", local:"departments"). 线程“主”中的异常javax.xml.bind.UnmarshalException:意外元素(uri:“”,local:“部门”)。 Expected elements are (none) 预期元素为(无)
Fixed it by declaring Departments
this way: 通过这样声明Departments
此问题:
@XmlRootElement(name="departments")
public class Departments {
List<Department> deptname;
public List<Department> getDeptname() {
return deptname;
}
public void setDeptname(List<Department> deptname) {
this.deptname = deptname;
}
}
See that question 看到那个问题
Have a try 试试
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