[英]How to instantiate base class with different generic types?
I am trying to create a 2nd constructor and call the parent class with a different generic type based on the constructor invocation. 我正在尝试创建第二个构造函数,并根据构造函数调用使用不同的泛型类型调用父类。 1 type is GroupTrackInfoDTO and the other one is TrackInfoDTO but I keep getting a compiling error
一种类型是GroupTrackInfoDTO,另一种类型是TrackInfoDTO,但我一直收到编译错误
Platform declaration clash: The following declarations have the same JVM signature
平台声明冲突:以下声明具有相同的JVM签名
My code: 我的代码:
class GetSettingsTask
: BizOperationTask {
private var mCallback: BizTaskCallback<TrackSettings>? = null
constructor(operation: BizOperation<GroupTrackInfoDTO>, mCallback: BizTaskCallback<TrackSettings>) : super(operation) {
this.mCallback = mCallback
}
constructor(o: BizOperation<TrackInfoDTO>, mCallback: BizTaskCallback<TrackSettings>) : super(o) {
this.mCallback = mCallback
}
if I add a dummy parameter to one of the constructors it worked but no idea why 如果我向构造函数之一添加一个哑元参数,则可以正常工作,但不知道为什么
constructor(o: BizOperation<TrackInfoDTO>, mCallback: BizTaskCallback<TrackSettings>, i: Int = 0) : super(o) {
this.mCallback = mCallback
}
They are the same JVM signature. 它们是相同的JVM签名。 You can define an abstract class (
AbstractTrackInfoDTO
) that is the parent of TrackInfoDTO
and GroupTrackInfoDTO
then declare the constructor as below: 您可以定义一个抽象类(
AbstractTrackInfoDTO
),它是TrackInfoDTO
和GroupTrackInfoDTO
的父TrackInfoDTO
,然后声明构造函数,如下所示:
constructor(operation: BizOperation<AbstractTrackInfoDTO>, mCallback: BizTaskCallback<TrackSettings>) : super(operation) {
this.mCallback = mCallback
}
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