获取Python中坐标列表的平均值

Question

I have a list of coordinates like [[1, 2, 2], [1, 2, 1], [1, 1, 1]] in python, and I want to get the average of them, such as in this case is [1, 1.66666666, 1.333333333] . However, I can't quite figure out how to do that. I have tried NumPy and basic list manipulation but they all failed to work. Can someone help me? I am using python 3.6 .

Answer 1

I guess this is what you are looking for:

data = [[1, 2, 2], [1, 2, 1], [1, 1, 1]]
average = [sum(x)/len(x) for x in zip(*data)]
print(average)

hope you're working with python 3.x.

Answer 2

You can use NumPy arrays for a column wise average as following. axis=0 computes the average columnwise. You can also use np.mean() here

data =  np.array([[1, 2, 2], [1, 2, 1], [1, 1, 1]] )

averaged = np.average(data, axis=0)
print (averaged)
# [1.         1.66666667 1.33333333]