golang 二进制文件不在 mips 上运行

Question

I'm using Go 1.11.4 on Windows 10 and I want to compile code for a MIPS 74Kc processor (Qualcomm Atheros QCA9558) running Linux. I compile with:

GOOS=linux GOARCH=mips go build

Get an executable, upload and run it and get:

Illegal instruction

Try again w/ GOARCH=mipsle and get:

./hello_mipsle_linux: line 1: syntax error: unexpected "("

What am I missing?

Answer 1

My host doing the build had an FPU but the board does not. Adding GOMIPS=softfloat fixed it:

GOOS=linux GOARCH=mips GOMIPS=softfloat go build

Answer 2

To list all possible MIPS architects available to your current build toolchain, use the go tool eg

$ go version

go version go1.12 darwin/amd64

$ go tool dist list | grep mips

linux/mips
linux/mips64
linux/mips64le
linux/mipsle

so probably one of the remaining GOARCH permutations you have not tried eg mips64 or mips64le .

uname -m would help to determine your target system's machine architecture.

Answer 3

I have a similar issue and it's solved by setting GOARCH=mipsle . This should work

GOOS=linux GOARCH=mipsle GOMIPS=softfloat go build

My core is MIPS 24KEc V5.0 , see my blog https://zyfdegh.github.io/post/202002-go-compile-for-mips/

If it's not OK, try these steps

1. Check the CPU architecture, Big-Endian or Little-Endian, by

$ lscpu | grep "Byte Order"

cat /proc/cpuinfo would also be helpful.

2. Check kernel info, mips or mips64, for me it's mips (32)

$ uname -a
Linux OpenWrt 4.14.151 #0 Tue Nov 5 14:12:18 2019 mips GNU/Linux

3. If it's Little-Endian, set GOARCH=mipsle , if it's 64bit Little-Endian, set set GOARCH=mips64le

Another related question Writing and Compiling Program For OpenWrt hope it helps.