[英]How to replace the contents of a group with a regular expression
This is the original string: 这是原始字符串:
233<C:\\Users\\Grapes\\Documents\\title.png>233<C:\\Users\\Grapes\\Documents\\title.png>33
This is the replaced string I want: 233<1>233<2>33
这是我想要的替换字符串:
233<1>233<2>33
I want to replace the file path in the string with the id I got after uploading to the server, but my program is in an infinite loop. 我想用上传到服务器后获得的ID替换字符串中的文件路径,但是我的程序处于无限循环中。
public void sendMessage(String msg) {
new Thread(()-> {
var pat = Pattern.compile("<(.*?[^\\\\])>");
var matcher = pat.matcher(msg);
int k = 0;
while (matcher.find()) {
matcher.replaceFirst("<" + k++ + ">"));
}
System.out.println(msg);
}).start();
}
You may use Matcher#appendReplacement
: 您可以使用
Matcher#appendReplacement
:
String s = "233<C:\\Users\\Grapes\\Documents\\title.png>233<C:\\Users\\Grapes\\Documents\\title.png>33";
int k = 0;
StringBuffer result = new StringBuffer();
Matcher m = Pattern.compile("<[^<>]*>").matcher(s);
while (m.find()) {
m.appendReplacement(result, "<" + ++k + ">");
}
m.appendTail(result);
System.out.println(result.toString());
// => 233<1>233<2>33
See the Java demo . 请参阅Java演示 。
The <[^<>]*>
pattern is enough in your case as it will match <
, then any 0 or more chars other than <
and >
and then <
. 在您的情况下,
<[^<>]*>
模式就足够了,因为它将匹配<
,然后匹配<
和>
以外的0个或多个字符,然后匹配<
。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.