在 SqlAlchemy 中过滤 Where 子句

Question

If I have the following postgres table.

users = Table('users', metadata,
Column('id', Integer, primary_key=True),
Column('name', String),
Column('fullname', String),
)

Suppose I want to get counts like so:

select count(*) filter (where name = 'name') as nnames, 
count(*) as n 
from users

Is it possible to do something similar to the above query with the sqlalchemy ORM using a query? I have not seen anything in the documentation. My current solution involves subquery and select .

Answer 1

Try something like this.

from sqlalchemy import func

Table.query.values(func.count().filter(Table.name == "name"), func.count())

I did so in flask-sqlalchemy