在python中使用方法startswith（）和re.findall（）提取确切的单词

Question

I have a text file like below,

&attri 'abc' real
&attri 'cde' real
&attri 'efg' {'0', '1'}
&attri 'ghi_jkl' real
&attri 'lmn' real
&attri 'nop' real
&attri 'pqr_stu_uvw' real
&attri 'xy_z' {'0', '1'}

I want to extract all the words 'abc', 'cde', 'efg', 'ghi_jkl', 'lmn', 'nop', 'pqr_stu_uvw', 'xy_z' from that file.

I wrote the following code, but it prints just [] .

import re

col = []

with open('text1.txt', 'r') as f:
    lines=f.readlines()
    for line in lines:
        l = line.strip()
        if l.startswith('&attri'):
            col.append(re.findall(r"'(.{1})'", l))
print(col)  

Thank you for helping me with this.

Answer 1

You don't need regex here considering that you always need to extract second word of each line out of file. Use split() and extract second split:

col = []

with open('text1.txt', 'r') as f:
    for line in f:
        if line.strip().startswith('&attri'):
            col.append(.strip("'"))

print(col)

Answer 2

Replace 2 lines with

       if l.startswith('&attri'):
            col.append(l.split()[1].strip("'"))

Answer 3

Try this:

import re

s = '''&attri 'abc' real
&attri 'cde' real
&attri 'efg' {'0', '1'}
&attri 'ghi_jkl' real
&attri 'lmn' real
&attri 'nop' real
&attri 'pqr_stu_uvw' real
&attri 'xy_z' {'0', '1'}'''


print(re.findall("'[a-zA-Z_]*'",s)

Result:

["'abc'", "'cde'", "'efg'", "'ghi_jkl'", "'lmn'", "'nop'", "'pqr_stu_uvw'", "'xy_z'"]